How to assign null value to a char array

[SunnyPriya]

Hi
I have a character array, say
char name[10] ;
I want to assign null value to it.
Can I do something like
name = null ;
or
strcpy(name,null) ;

Help is needed.

Regards
SunnyPriya Joshi
:)

[WildCat]

memset(name, 0, sizeof(char) * 10)

[Elrond]

2 possibilities:

If you want to use it as a string, then, set the fisrt character to null should be the best:
name[0] = '\0';

If you want to put all the elements of your array to nul, then use memset as WildCat says.

[JMS]

Null is a pointer value. So you could say

char *pszMyString = Null;

and thus set a pointer to NULL but not set a string to NULL.

Now the termination character for a string is also called the NULL terminator but it is something different than NULL which as I said is a pointer value. The NULL termination character for a string is the ascii value absolute Zero... [ 0 ]. or '\0'.

One can set the first character of a character array to this value which effectively ends the string at element Zero.. Like this..

char szMyString[5] = "abcd"

szMyString[0] = '\0';

Now this doesn't exactly overwrite the entire array. Anybody trying to access this array as a string will just think it ends at element 0. The contents of the szMyString array looks like this..
0 123 4
'\0bcd\0'

To overwrite the entire array with the Null terminator use memset as has already been discussed..

memset ( (void *) &szMystring, '\0', sizeof(szMystring));

this will make the array contents
0 1 2 3 4
'\0\0\0\0\0'

get it?