Carl Waldbieser
July 12th, 2002, 06:27 PM
I am using MSXML4 (SP1) on both Win98 and Win2000. When I apply an XSLT transform with an output method of "text", an extra carrige return is printed out at th end of each line. The following transform:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="text" encoding="UTF-8" />
<xsl:variable name="CR" >
<xsl:text>&#xA;</xsl:text>
</xsl:variable>
<xsl:template match="/">Hello<xsl:value-of select="$CR" />World!</xsl:template>
</xsl:stylesheet>
produces the following output when applied to any valid document:
Hello
World!
Looking at the file with a hex editor, I can see:
48 65 6c 6c 6f 0d 0d 0a 57 6f 72 6c 64 21
It appears as though there is an extra 0d before the 0d 0a (CR LF). Any ideas why this is happening?
Thanks in advance,
Carl Waldbieser
waldbie@attlobal.net
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="text" encoding="UTF-8" />
<xsl:variable name="CR" >
<xsl:text>&#xA;</xsl:text>
</xsl:variable>
<xsl:template match="/">Hello<xsl:value-of select="$CR" />World!</xsl:template>
</xsl:stylesheet>
produces the following output when applied to any valid document:
Hello
World!
Looking at the file with a hex editor, I can see:
48 65 6c 6c 6f 0d 0d 0a 57 6f 72 6c 64 21
It appears as though there is an extra 0d before the 0d 0a (CR LF). Any ideas why this is happening?
Thanks in advance,
Carl Waldbieser
waldbie@attlobal.net