Meeting troubles when compiling simple STL program.

[George2]

Hi, everyone!

I meet with the following trouble when compiling the
following simple STL program.

The error message is, ostream_iterator undeclared.
My IDE is VC 6.0.

Here are the source codes,

--------
#include "iterator"
#include "iostream"

void main()
{
ostream_iterator<int> r (cout);
*r = 0;
}
--------


Thanks in advance,
George

[SeventhStar]

dont forget to write
either
std:: ostream_iterator r;
or
using namespace std;
aafter the #includes

[Andreas Masur]

Everything of the STL is declared within the namespace 'std'. Therefore you need to map the namespace to your application as mentioned.

The following shows you the four different methods to map a namespace...

// Using the full member name, including the namespace it belongs to:
std::cout << "Hello World";


// By taking advantage of Using-Declarations:
using std::cout; // This declares cout in the current
// scope as synonym for std::cout
cout << "Hello World";


// By taking advantage of Using-Directives:
using namespace std; // Which specifies that the current
// scope can refer to names in the
// 'std' namespace without using
// full qualifiers. This is mostly
// used when porting legacy code.
cout << "Hello World";


// Using aliases:
namespace X
{
namespace Y
{
class Z { ... };
}
}

X::Y::Z // The full qualifier for 'Z' is
// 'X::Y::Z'

namespace w = X::Y; // This declares 'w' as an alias for
// namespace 'X::Y'

w::Z // Access 'Z' using 'w::Z'

[George2]

Thanks!


Originally posted by Andreas Masur
Everything of the STL is declared within the namespace 'std'. Therefore you need to map the namespace to your application as mentioned.

The following shows you the four different methods to map a namespace...

// Using the full member name, including the namespace it belongs to:
std::cout << "Hello World";


// By taking advantage of Using-Declarations:
using std::cout; // This declares cout in the current
// scope as synonym for std::cout
cout << "Hello World";


// By taking advantage of Using-Directives:
using namespace std; // Which specifies that the current
// scope can refer to names in the
// 'std' namespace without using
// full qualifiers. This is mostly
// used when porting legacy code.
cout << "Hello World";


// Using aliases:
namespace X
{
namespace Y
{
class Z { ... };
}
}

X::Y::Z // The full qualifier for 'Z' is
// 'X::Y::Z'

namespace w = X::Y; // This declares 'w' as an alias for
// namespace 'X::Y'

w::Z // Access 'Z' using 'w::Z'

[George2]

Originally posted by Andreas Masur
Everything of the STL is declared within the namespace 'std'. Therefore you need to map the namespace to your application as mentioned.

The following shows you the four different methods to map a namespace...

// Using the full member name, including the namespace it belongs to:
std::cout << "Hello World";


// By taking advantage of Using-Declarations:
using std::cout; // This declares cout in the current
// scope as synonym for std::cout
cout << "Hello World";


// By taking advantage of Using-Directives:
using namespace std; // Which specifies that the current
// scope can refer to names in the
// 'std' namespace without using
// full qualifiers. This is mostly
// used when porting legacy code.
cout << "Hello World";


// Using aliases:
namespace X
{
namespace Y
{
class Z { ... };
}
}

X::Y::Z // The full qualifier for 'Z' is
// 'X::Y::Z'

namespace w = X::Y; // This declares 'w' as an alias for
// namespace 'X::Y'

w::Z // Access 'Z' using 'w::Z'

[George2]

Thanks, SeventhStar buddies!

George

Originally posted by SeventhStar
dont forget to write
either
std:: ostream_iterator r;
or
using namespace std;
aafter the #includes