How to get the file content in the server, posted using <input type=file>

Hi folks,

i have one form that will send the client file to the server. The html code for this is

&lt;form action="httt://servlet:8080/servlet/upload" Method= POST enctype="multipart/form-data"&gt;
&lt;input type=file name=file_name&gt;
&lt;input type=submit&gt;
&lt;/form&gt;

I dont know how to get the file content in the server server side using servlets.

Do please let me know. My id is xavier_wilson@hotmail.com


Thanks in advance

wilson.

[meherss]

See this code..
Posted some time back by Leon

//(the class base64 encodes the attachment, there is just attachment without any message body)

out.println("DATA");
out.flush();

line = in.readLine(); //354 ...
if(!line.startsWith("354"))
{
System.out.println("ERROR: DATA");
return;
}

//message:
out.println("From: " + fromName + " &lt;" + from + "&gt;");
out.println("Reply-To: " + from);
out.println("X-Mailer: Java SMTP v1.0");
out.println("MIME-Version: 1.0");
out.println("To: " + to);
out.println("Subject: " + subject);
out.println("Content-Type: multipart/mixed; boundary="+(char)34+"=============0123456789=="+(char)34);
out.println("");
out.println("This is a multi-part message in MIME format.");
out.println("");
out.println("--=============0123456789==");


out.println("Content-Type: application/octet-stream; name="+(char)34+filename+(char)34);
out.println("Content-Transfer-Encoding: base64");
out.println("Content-Disposition: attachment; filename="+(char)34+filename+(char)34);
out.println("");

base64 mm=new base64(attachment,attlen,out);

out.println("--=============0123456789==--");

out.println(".");
out.flush();





Hope this gives you some clues...

Meher