How to find difference between two dates dd/mm/yyyy?

[Pescador34]

Title ??? :)

[cilu]

COleDateTime t1(2005,3,17,0,0,0);
COleDateTime t2(2004,3,1,0,0,0);

COleDateTimeSpan ts = t1 - t2;

[Bni]

difftime: Computes the difference between two times.

mktime: Converts time to calendar format.

[Pescador34]

Thanks,

i use it but to separate dates i make this
int HelpingHand::DifferenceBetweenDates(char *date1,char *date2){

int day1,month1,year1,day2,month2,year2;
int totalsep = 0, i = 0, j = 0 ;
char num[4];

ZeroMemory(num, sizeof(num));
while(date1[i] != '\0'){
TRACE("%c",date1[i]);
if ( totalsep == 0 && (date1[i] == '-' || date1[i] == '/')){
day1 = atoi(num);
ZeroMemory(num, sizeof(num));
totalsep += 1;
j=0;
i++;
continue;
}else if(totalsep == 1 && (date1[i] == '-' || date1[i] == '/')){
month1 = atoi(num);
ZeroMemory(num, sizeof(num));
totalsep += 1;
j=0;
i++;
continue;
}
num[j] = date1[i];
i++;
j++;
}
year1 = atoi(num);
ZeroMemory(num, sizeof(num));

totalsep = 0;
i=0;
j=0;
TRACE("\n");
while(date2[i] != '\0'){
TRACE("%c",date2[i]);
if ( totalsep == 0 && (date2[i] == '-' || date2[i] == '/')){
day2 = atoi(num);
ZeroMemory(num, sizeof(num));
totalsep += 1;
j=0;
i++;
continue;
}else if(totalsep == 1 && (date2[i] == '-' || date2[i] == '/')){
month2 = atoi(num);
ZeroMemory(num, sizeof(num));
totalsep += 1;
j=0;
i++;
continue;
}
num[j] = date2[i];
i++;
j++;
}
year2 = atoi(num);
ZeroMemory(num, sizeof(num));


COleDateTime t1(year1,month1,day1,0,0,0);
COleDateTime t2(year2,month2,day2,0,0,0);

COleDateTimeSpan ts = t2 - t1;

return ts;

}
do you can know more simple ;). Thanks again.

difftime: Computes the difference between two times.

mktime: Converts time to calendar format. Time? Data....

[Pescador34]

In another form....

date if give like:
dfCreated = 16-03-2005 11:17:28
dNow = 17-03-2005 18:41:20

i try to use this...

int HelpingHand::DifferenceBetweenDates(char *dfCreated,char *dNow){

CTime diff = (dNow - dfCreated);

CString stemp = diff.Format( "Total days: %D, hours: %H, mins: %M, secs: %S" );
...


output = Total days: , hours: 00, mins: 01, secs: 12 !!!!!!!


sorry the confusion...:o

[Bni]

What I had in mind was more like...

#include <stdio.h>
#include <time.h>

#define EXTRACT_HOUR(sec) ((sec)/(60*60))

int main(void)
{
time_t t1, t2, t3;
struct tm datetime;

datetime.tm_year = 2005 - 1900;
datetime.tm_mon = 03 - 1;
datetime.tm_mday = 17;
datetime.tm_hour = 1;
datetime.tm_min = 2;
datetime.tm_sec = 3;
datetime.tm_isdst = 0;
t1 = mktime(&datetime);
printf("Date and time #1: %s\n", ctime(&t1));

datetime.tm_year = 2005 - 1900;
datetime.tm_mon = 03 - 1;
datetime.tm_mday = 17;
datetime.tm_hour = 8;
datetime.tm_min = 7;
datetime.tm_sec = 6;
datetime.tm_isdst = 0;
t2 = mktime(&datetime);
printf("Date and time #2: %s\n", ctime(&t1));

t3 = t2-t1;
printf("Total number of seconds : %ld \n", t3);
printf("Relative number of hours is: %ld heures\n", EXTRACT_HOUR(t3) );

return 0;
}

I dont know any shorter