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Post questions or answers on Python and related topics.enThu, 25 Dec 2014 21:14:30 GMTvBulletin60http://forums.codeguru.com/images/misc/rss.pngCodeGuru Forums - Python
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Please recommend a Python book
http://forums.codeguru.com/showthread.php?548495-Please-recommend-a-Python-book&goto=newpost
Tue, 23 Dec 2014 21:01:21 GMTI need a Python book which mostly explains advanced topics in depth in Python. Any Python guru here please recommend an excellent Python book for me. Tons of thanks.I need a Python book which mostly explains advanced topics in depth in Python. Any Python guru here please recommend an excellent Python book for me. Tons of thanks.
]]>Pythondullboyhttp://forums.codeguru.com/showthread.php?548495-Please-recommend-a-Python-bookcalculating paternity index of single inconsitency in mutation with python
http://forums.codeguru.com/showthread.php?548193-calculating-paternity-index-of-single-inconsitency-in-mutation-with-python&goto=newpost
Tue, 02 Dec 2014 12:54:30 GMTPYTHON PROGRAMMING CODE TO ASSERTAIN THESE:
person genotype
mother ab
child bc
alleged father de
X = P(man without C will contribute C)
X = P(contributed gene will mutate) * P(mutated gene will be a C)
m = observed rate of mutations/meiosis for the locus
P(mutated gene will be a C) ie. Frequency of C allele = C
X = C * m
For the numerator (X) Probability = 2ab x 2de x 0.5 x m x C
In order to explain this evidence the denominator
must calculate the probability that the paternal allele
is C and a random man would have a genotype
inconsistent with paternity at this locus
Y = P(paternal allele is C and random man has no C allele)
= P(paternal gene is C) * P(random man has no C allele)
P(paternal allele will be a C) ie. Frequency of C allele = C
P(random man has no C allele) = probability of exclusion
Y = C * A
For denominator (Y) Probability = 2ab x 2de x 0.5 x C x A
hence the final result should be:
PI = X/Y
PI = (2ab * 2de * 0.5 * C * m ) / (2ab * 2de * 0.5 * C * A)
PI = m/A
N:B where PI is Paternity IndexPYTHON PROGRAMMING CODE TO ASSERTAIN THESE:

person genotype

mother ab

child bc

alleged father de

X = P(man without C will contribute C)
X = P(contributed gene will mutate) * P(mutated gene will be a C)
m = observed rate of mutations/meiosis for the locus
P(mutated gene will be a C) ie. Frequency of C allele = C
X = C * m

For the numerator (X) Probability = 2ab x 2de x 0.5 x m x C

In order to explain this evidence the denominator
must calculate the probability that the paternal allele
is C and a random man would have a genotype
inconsistent with paternity at this locus
Y = P(paternal allele is C and random man has no C allele)
= P(paternal gene is C) * P(random man has no C allele)

P(paternal allele will be a C) ie. Frequency of C allele = C
P(random man has no C allele) = probability of exclusion

Y = C * A

For denominator (Y) Probability = 2ab x 2de x 0.5 x C x A

hence the final result should be:

PI = X/Y

PI = (2ab * 2de * 0.5 * C * m ) / (2ab * 2de * 0.5 * C * A)

PI = m/A
N:B where PI is Paternity Index
]]>Pythonleequest77@gmail.comhttp://forums.codeguru.com/showthread.php?548193-calculating-paternity-index-of-single-inconsitency-in-mutation-with-python