question about a struct pointer parameter

Hello everybody!
Recently while i was experimenting with some code written in c++ i noticed something that confused me a bit. In that code i had to deal with 2 structs :

Code:

---

struct date
{
    string day;
    int month;
    int dday;
  int year; };

---

and the other struct

Code:

---

struct note
{
    date d;
    string notice;  };

---

I noticed that when i was passing in a function i built, an instance of note struct as a pointer parameter my program kept crashing continuously, although compiler wasn't complaining. To make myself clear :

Code:

---

void myFunction(note* n, ...other parameters...)
{
    cout << n->d.day << endl;
  cout << n->d.month << endl;
    etc...
}

---

I'm sure that my program crashed because of that piece of code

Code:

---

n->d.day

---

i'm sure because i tested it in debug mode.
When i wrote my function differently i had no problem running my program :

Code:

---

void myFunction(note& n, ..other parameters...)
{
    cout << n.d.day << endl;
    cout << n.d.month << endl;
  etc...
  }

---

Has anyone got an idea why the pointer parameter and the arrow
caused that problem? Looking forward to reading your ideas and thoughts...Thank you in advance for your time...

vanalex

I doubt that could be the cause.

Most likely that std::string is getting corrupted somehow, though. Make sure you aren't trying to use memset, memcpy, or anything like that.

Thank you very much for your reply Lindley, but i found what caused the whole problem. The . operator precedes the -> operator in expressions so i had to write my code like this:

Code:

---

(n->).d.day

---

wrong way without parenthesis:

Code:

---

n->d.day

---

vanalex

No wrong again!

RIGHT CODE

Code:

---

(n->d).day

---

sorry...:)

Quote:

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Originally Posted by vanalex

No wrong again!

RIGHT CODE

Code:

---

(n->d).day

---

sorry...:)

---

I don't think that is the reason. -> and . operators have the same preference and they have left to right associativity.
http://cppreference.com/wiki/operator_precedence

Also, interpreting n->d.day as n->(d.day) does not make sense. What exactly is that supposed to mean to the compiler?