Try Catch Question

I need to use try...catch so if the user enters more then 10 digits

Code:

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#include <iostream>

int main( int argc, const char*argv )
{
        int numInput = 0, avgCount = 0, totalCount = 0; 
        float average = 0;

        while( numInput != 99 )
        {
               
                std::cout << "Enter a Number (Max 10 digits)(99 to Exit): ";
                std::cin >> numInput;

                if ( numInput != 99 )
                {
                        totalCount += numInput;
                        avgCount += 1;
                }
        }
       
        try
        {
                if( avgCount == 0 )
                {
                        throw 0;
                }
                average = totalCount / avgCount;
        }
        catch(...)
        {
                std::cout << "Divide by Zero error" << std::endl;
                totalCount = 0;
        }
       
        std::cout << "Average of all Inputs: " << average << std::endl;

        system("pause");
        return 0;
}

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Please use code tags for posting code.

Quote:

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I need to use try...catch so if the user enters more then 10 digits

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If you have a question, it helps to actually ask the question.

Your main signature is wrong. It should be:

Code:

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int main()

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Code:

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int main(int argc, char** argv)

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Don't use system("pause"), seePause Before Exiting a Console Application

Use code tags to post code.

So check the length of user input, read the user input as a string. Then you can count the number of characters and convert it to an int.

thank you