Receive file sended with TransmitFile()

Hi Everybody,

The MSDN shows how to use the API TransmitFile() to send a file over a conneciton-oriented socket.. but it does not show you how to receive it!

Is it done with the recv function or is it done in any other way?

I want this becouse I'm making a chat program. By now it is a frame with a menubar with two (useful, there are more non-useful) entries. Both options creates a child window, but server option sets up a server, and client options conects to a server.

I'm a bit strucked in the function of sending and receiving files. So any help is wellcome :)

AFAIK, you can use receive() function to receive file data. The TransmitFile() is just an optimized sending function in sender side.

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Originally Posted by [email protected]

AFAIK, you can use receive() function to receive file data. The TransmitFile() is just an optimized sending function in sender side.

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Ok, but another question, Is there a function to know when it's a file and not text? and How to rebuild the file on the receiver side?

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Originally Posted by pedro00pedro

Ok, but another question, Is there a function to know when it's a file and not text? and How to rebuild the file on the receiver side?

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You have to build a mechanism (protocol) so the receiver knows received data has to be saved into file.

To rebuild the file, just save all receive data into file, but as i mention above, you have to build a mechanism how to transfer the file. The good example may be FTP protocol.

I forgot to tell you. There is no function to know received data is a file data or just a text.
I suggest you to see RFC959 (File Transfer Protocol) as an example.

http://datatracker.ietf.org/doc/rfc959/