Celcius Conversion Loop

So everything seems to be working fine here, but after the first calculation that converts 0C to 32F, it just adds increments of 1 to each Fahrenheit. Why isn't the formula being repeated for each increasing value of Celcius? Help would be greatly appreciated, as I have spent hours trying to figure this out.:wave:

Code:

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# include <iostream>
# include <iomanip>
using namespace std;

int main()
{
       
        double c;
        cout << setw(4) << "Celcius" << setw(7) << "" << "Fahrenheit" << endl;
       

       
        for (c = 0; c <= 20; c++)
                {
                        double f = (9/5) * c + 32;
                       
                               

                        cout << setw(4) << c << setw(7) << " " << " " << " " << " " << f << endl;
        }

                         
       
               
        return 0;
        }

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Quote:

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Originally Posted by bertonius

So everything seems to be working fine here, but after the first calculation that converts 0C to 32F, it just adds increments of 1 to each Fahrenheit. Why isn't the formula being repeated for each increasing value of Celcius? Help would be greatly appreciated, as I have spent hours trying to figure this out.:wave:

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What do you think this gives you?

Code:

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(9/5)

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When you divide an integer by an integer, the result is an integer.

Regards,

Paul McKenzie

Thank you, Paul. I changed the formula to (1.8 * c) + 32 instead, and it is working. Here's what it looks like now:

Code:

---

# include <iostream>
# include <iomanip>
using namespace std;

int main()
{
       
        int c;
        cout << setw(4) << "Celcius" << setw(7) << "" << "Fahrenheit" << endl;
       

       
        for (c = 0; c <= 20; c++)
                {
                        int f = (1.8 * c) + 32;
                       
                               

                        cout << setw(4) << c << setw(7) << " " << " " << " " << " " << f << endl;
        }

                         
       
               
        return 0;
        }

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Quote:

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Originally Posted by bertonius

Thank you, Paul. I changed the formula to (1.8 * c) + 32 instead, and it is working.

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You could have easily just done this:

Code:

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(9.0 / 5.0)

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The numerator and denominator are both floating-point (double), so the result will be a double instead of having the truncation done as in (9/5).

Regards,

Paul McKenzie