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Hi,
on running program below - I get this as output
9 5 11 1
3 5 6 2
3 11 9 1
2 5 1 3
5 6 9 1
2 6 3 2
2 9 5 1
Can anyone explain this for me ? Thanks !!Code:void crazy(int a, int b, int m, int n){
if(n == 0)
return;
crazy(a+m, b, m+b, n-1);
printf("\n %d %d %d %d \n", a, b, m, n );
crazy(a,b+m,m+a,n-1);
}
int main(){
crazy(2,5,1,3);
}
Which line of the code snippet you have posted is unclear for you?
In few words: function crazy is called recursively until its last paremeter will be zero. And function printf prints out the values of parameters passed into crazy.
Sounds like homework. In any case, it's a simply recursive calls crazy in a tree like fashion, "in-order".Quote:
Originally Posted by mithlesh
Simply tracing your code with a pen and paper would help here:
Code:+------>crazy(20,5,16,0);
+------>crazy(9,5,11,1);
| +------>crazy(9,16,20,0);
|
+------>crazy(3,5,6,2);
| |
| | +------>crazy(12,11,20,0);
| +------>crazy(3,11,9,1);
| +------>crazy(3,20,12,0);
crazy(2,5,1,3);
|
| +------>crazy(14,6,15,0);
| +------>crazy(5,6,9,1);
| | +------>crazy(5,15,14,0);
| |
+------>crazy(2,6,3,2);
|
| +------>crazy(7,9,14,0);
+------>crazy(2,9,5,1);
+------>crazy(2,14,7,0);