Need to add pause to existing C++ program

I have been asked to add a pause to an existing C++ program.
The user does not want to use the Windows builtin scheduler for reasons they won't share with me.
Is the correct way of doing this something like:-
void Sleep(10000);

Define "pause".
Note that this

Code:

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Sleep(10000);

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will freeze your App. So its GUI will be completely "dead" for the 10 seconds and it would be at least surprised the users!
Is it what you want? :confused:

Or you can send your app to a loop for 10 sec

for(int i = 0; i < 1000000; i++) // A basic for loop

or :

#define DELAY 128000 // increase the delay value if you wish

void delay(void);


void delay(void)
{
long int t;

for (t=1; t< DELAY ; t++ )
}

QUOTE=lio_cs;1861155]Or you can send your app to a loop for 10 sec

for(int i = 0; i < 1000000; i++) // A basic for loop
[/QUOTE]Well, why do you think that this loop will be executed for exactly 10 seconds? :confused: :rolleyes:[

Quote:

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Originally Posted by lio_cs

... or :

#define DELAY 128000 // increase the delay value if you wish

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And how exactly has OP to *increase* this magic 128000 number to get exactly 10 seconds on any user PC? :confused:
:thumbd:

Quote:

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I have been asked to add a pause to an existing C++ program.

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Is your program a commandline program or does it has a GUI ?

Quote:

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Originally Posted by VictorN

QUOTE=lio_cs;1861155]Or you can send your app to a loop for 10 sec

for(int i = 0; i < 1000000; i++) // A basic for loop

---

Well, why do you think that this loop will be executed for exactly 10 seconds? :confused: :rolleyes:[

And how exactly has OP to *increase* this magic 128000 number to get exactly 10 seconds on any user PC? :confused:
:thumbd:[/QUOTE]

Code:

---

#include <stdio.h>
#define DELAY 2560000000
struct my_time{
int hours;
int minutes;
int seconds;
};
void display(struct my_time *t);
void update(struct my_time *t);
void delay(void);

int main(void)
{
struct my_time systime;

systime.hours = 0;
systime.minutes = 0;
systime.seconds = 0;

  for(;;)
  {
    update(&systime);
    display(&systime);
  }
 
  return 0;
}

void update(struct my_time *t)
{
  t->seconds++;
    if(t->seconds==60)
      {
        t->seconds = 0;
        t->minutes++;
      }
  if(t->minutes==60)
    {
      t->minutes = 0;
      t->hours++;
    }
  if(t->hours==24) t->hours = 0;
  delay();
 
}

void display(struct my_time *t)
{
  printf("&#37;02d:", t->hours);
  printf("%02d:", t->minutes);
  printf("%02d:\n", t->seconds);
}

void delay(void)
{
  unsigned long int t;
  for(t=1;t<DELAY;t++);
}

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ok this will cause a 10 sec delay predefined by the programmer (DELAY)

As Victor said, he needs to define pause and give more information about his app. Whatever it means, I believe it's relatively safe to say the solution doesn't lie in a busy/wait loop.

Quote:

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Originally Posted by lio_cs

Well, why do you think that this loop will be executed for exactly 10 seconds? :confused: :rolleyes:[

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But it is what OP seemed to want to implement using Sleep(10000) which will freeze the current thread for exactly 10 seconds:

Quote:

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Originally Posted by straygrey

I have been asked to add a pause to an existing C++ program....
Is the correct way of doing this something like:-
void Sleep(10000);

---

Quote:

---

Originally Posted by lio_cs

Code:

---

#include <stdio.h>
#define DELAY 2560000000
struct my_time{
int hours;
int minutes;
int seconds;
};
void display(struct my_time *t);
void update(struct my_time *t);
void delay(void);

int main(void)
{
  ....
  return 0;
}

void update(struct my_time *t)
{
    .... 
}

void display(struct my_time *t)
{
  .....
}

void delay(void)
{
  .....
}

---

ok this will cause a 10 sec delay predefined by the programmer (DELAY)

---

Well, I don't have enogh time to test your code; I just hope it will work...
The only question is: why waste time to develop/write/test some code that is supposed to do exactly the same as Sleep does?!
Besides. this code would just unusefully load CPU!