passing pointers of array to function

Hello everyone,
ive been googleing this all day and havent found an answer yet.
i want to create an array in int Main() and then pass a pointer referencing the
array to a function to fill it.
This is how far i have gotten:

Code:

---

int main(void)
{
        test();
        float dat[1000];
        readnprint(&dat[0]);
      /*
        other code her
        */
}

void readnprint(float *base_ptr)
{
    //init ifstream etc etc..
        float addr=base_ptr;
        while (!ins.eof())
        {
                ins>>x;
                float f;
                if(from_string<float>(f, string(x), dec)) //parse float?
                  {
                        addr=(base_ptr)+(sizeof(float)*cnt)          //steps through array by sizeof(float)
                        *(float)addr=f;  //have this assign the value to memory location (problem)
                  }
                  else
                  {
                        cout << "from_string failed" << endl;
                  }
                cnt++;
        }
        ins.close();
}

---

im sure im just tired and not thinking right, does anyone have a better/working way of doing this?

thanks

-maze

Quote:

---

Originally Posted by madmaze

im sure im just tired and not thinking right, does anyone have a better/working way of doing this?

---

Why are you working with arrays? A proper container (e.g., std::vector) is more robust and safer.
As for the other part of your problem, this is easily solvable with std::generate and a functor.

This is one way of doing it.

Code:

---

void main()
{
  float dat[1000];
  readnprint(dat, 1000);
}

void readnprint(float* base_ptr, int size)
{
  for (int i = 0; i < size; ++i)
  {
      base_ptr[i] = i;
  }
}

---

Quote:

---

Originally Posted by _Superman_

This is one way of doing it.

---

Note that void main() should be int main(), as in madmaze's original example.

not sure what i was thinking last night.. simply passing by ref is the easiest..
thanks for the responses =)