insert date value into sql using php?

i want to store date in many fields of sql server 2000, the date field having the datatype datetime and i pass the value to the date field like below

Code:

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$now=date("m/d/Y h:i:s A");
 
            mssql_bind($stmt,"@s_date", $var1,SQLINT4);

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first variable got insert the now date successfully but other dates values didnt insert now value it store like 1/2/1900 12:00:00 AM


why it behave like this can any one suggest me answer to this


thanks
sona

Date formatting for SQL and SQL derivatives is "YYYY/MM/DD HH:MM:SS" and not as you have it. Note that the hour is 24, not 12.

hi thanks for ur reply

i want this format to be stored in database "m/d/Y h:i:s A" ?

how to i achieve this using php and store it in database.

The only way to do that is to make the column of varchar type. But, that's a very, very poor implementation because then you lose the date/time object.

Use the proper format and just display the formatted date with PHP. Why do you think that PHP has such an extensive date/time function set?

hi how to bind the post value of date using php for sql

can u give sample code ..

Code:

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$now=date("Y/M/D H:I:S");

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but it produce like this Jul 5 1905 12:00AM

Please start trying to do some of your own work...http://ar2.php.net/manual/en/function.date.php

hi

what is datatype for bind the datetime into msssql. i used sqlint4 but it is not correctly bind value.

i know about the date functions.

Code:

---


$now="1/2/2003";
 
            mssql_bind($stmt,"@s_date", $now,SQLINT4);

---

@s_date datetime

i bind now variable to datefield but in database didnt store this value instead of it store the default time

1/2/1900 12:00:00 AM

the problem is the datatype i passed or data value which is i used ? can u guide me

That's because binding requires that the variable be of the same time. Since PHP does not have a datetime type variable, you need to use a query, not a bind.