When the button is clicked, I want the file to be opened.
The file will be in the same directory as the visual basic project.
Therefore, I need the code to open the file using "app.Path".
Any solutions?
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When the button is clicked, I want the file to be opened.
The file will be in the same directory as the visual basic project.
Therefore, I need the code to open the file using "app.Path".
Any solutions?
What kind of file are we talking about?
it's an XPS file (.xps).Quote:
Originally Posted by dglienna
When the button is clicked, I want that file to be opened in windows.
You must get the full path of the file, like this
App.Path & "\" & <name.ext>
Once you have it, you can call the ShellExecute API function passing as param the string you got before.
And OPEN will open the text file, but not decode the XML inside of it.
http://www.fileinfo.com/extension/xps
The OPEN argument is not needed and you can also leave a blank string, because the ShellExecute has the open command as default one. See a guide on this API, that provided by AllAPI.net is a very good one.Quote:
Originally Posted by dglienna
Enjoy! :wave: