What is the purpose of @ here?

Here is the example,

Code:

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string ex = @"This has a carriage return\r\n"

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Thanks.

It declares the string to be literal. It will therefore NOT interpret \r as a carriage return escape sequence and \n as a newline escape sequence. Read more at http://msdn.microsoft.com/en-us/libr...(v=vs.71).aspx

Quote:

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Originally Posted by LarryChen

Here is the example,

Code:

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string ex = @"This has a carriage return\r\n"

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Thanks.

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Really, Larry? Instead of posting a question like this to the forum, why not remove the @ and see what happens? Then look in msdn if you still have questions.