understanding pointers

Hi,
I am new to pointer world. I have started programming in c++ and have basic knowledge in c.

Code:

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    char y[]="helloo";
    char *p=y;
    cout<< p[1];

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This prints 'e'

if I print:

Code:

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cout<< p

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I get hello. I am unable to underatnd why. It should actually print address of y array!

Quote:

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It should actually print address of y array!

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It prints correctly. p is a pointer to a char which has been set to the address pointed to by y. cout sees that the type of p is of char * (pointer to char) and so treats it as a c null-terminated string and prints its contents.

@PM2kaud- Thank you for your reply.
So basically with string, the base address is passed and

Code:

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cout

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prints until it finds '\0'

Please correct me, if I am wrong.

Quote:

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Originally Posted by 2kaud

It prints correctly. p is a pointer to a char which has been set to the address pointed to by y. cout sees that the type of p is of char * (pointer to char) and so treats it as a c null-terminated string and prints its contents.

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Yes - for a c-style null terminated string. In c++ there is also a class called string which is very different.

Ohh.
Thank you once again.

Quote:

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Originally Posted by 2kaud

Yes - for a c-style null terminated string. In c++ there is also a class called string which is very different.

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