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Can somebody help me with making a bar chart in C++ ?
I have to make a bar chart where each * represents 100. It should display like this after the user has inputted the cin for store sales.
Store 1: *******
Store 2: *******
Store 3: *******
Store 4: *******
Store 5: *******
Use a for-loop.
Although you could directly use a loop, it may be simpler to just create (and immediately print) a string of asterisks with the desired length, since std::string has a suitable constructor.
how would i use the for loop for this?
consider
http://msdn.microsoft.com/en-us/library/b80153d8.aspxCode:
for( unsigned int I = 0; I < 10; ++I )
{
cout << "*";
}
this is very basic and could be easily found by google. please do some research
yeah so how would i make it so the users input each represent 100 in the chart?
i suppose you start with some math. maybe int points = total / 100; ?
can you please just help me out? I've never learned this material before. Im suppose to make a bar chart where store1=1000, store2= 1200, store3=1800, store4= 800, store5 =1900. and each asterisk will represent 100.
so far this is what i got..
i just dont know how to do the bar chart part..Code:#include<iomanip>
using namespace std;
int main()
{
int store1, store2, store3, store4, store5;
cout << "Enter today's sales for store 1.\n";
cout << "Enter a value between 0 and 4000: ";
cin >> store1;
while ( store1 % 100 != 0 || store1 < 0 || store1 > 4000 )
{
cout << "Invalid sales amount: " << store1 << endl;
cout << "Sales must be multiple of 100 in range 0-4000, inclusive.\n";
cout << "Enter today's sales for store 1.";
cin >> store1;
}
cout << "Enter the sales for store 2.";
cin >> store2;
while ( store2 % 100 != 0 || store2 < 0 || store2 > 4000 )
{
cout << "Invalid sales amount: " << store2 << endl;
cout << "Sales must be multiple of 100 in range 0-4000, inclusive.\n";
cout << "Enter today's sales for store 2.";
cin >> store2;
}
cout << "Enter the sales for store 3.";
cin >> store3;
while ( store3 % 100 != 0 || store3 < 0 || store3 > 4000 )
{
cout << "Invalid sales amount: " << store3 << endl;
cout << "Sales must be multiple of 100 in range 0-4000, inclusive.\n";
cout << "Enter today's sales for store 3.";
cin >> store3;
}
cout << "Enter the sales for store 4.";
cin >> store4;
while ( store4 % 100 != 0 || store4 < 0 || store4 > 4000 )
{
cout << "Invalid sales amount: " << store4 << endl;
cout << "Sales must be multiple of 100 in range 0-4000, inclusive.\n";
cout << "Enter today's sales for store 4.";
cin >> store4;
}
cout << "Enter the sales for store 5.";
cin >> store5;
while ( store5 % 100 != 0 || store5 < 0 || store5 > 4000 )
{
cout << "Invalid sales amount: " << store5 << endl;
cout << "Sales must be multiple of 100 in range 0-4000, inclusive.\n";
cout << "Enter today's sales for store 5.";
cin >> store5;
}
i have. if i write too much more, i would be handing your assignment in too.Quote:
can you please just help me out?
I highlighted the 10... for a reasonCode:
int points = store4 / 100;
for( unsigned int I = 0; I < 10; ++I )
{
cout << "*";
}
that code is redundantQuote:
so far this is what i got..
im thinking for ( store1 = 0; store1 / 100; ++store1 ) ? this doesnt work
let's think here for a moment. did store1 hold the value for the store 1? if so, you effectively destroyed its value. store1 / 100 isn't right. the first test would equal false since 0 / 100 is 0. ++store1... well would count up if it ran, but when would it stop?Quote:
for ( store1 = 0; store1 / 100; ++store1 ) ?
loop up how to use the for statement.....................
..dude i am reading my textbook and it doesnt say anything about making bar charts with the for loop. if you are not going to try to help please do not answer at all okay? believe it or not there are beginners in this world
Yes, but that is because you used store1 as the loop counter. You should use another variable. Also, note that the truncation means that if the number is less than 100, no asterisk will be displayed. Is this intended?Quote:
Originally Posted by Sabensohn70
EDIT:
Read Joeman's explanation of why your loop did not work. If you refuse to listen to anything other than a direct solution, you will not gain in understanding, and thus remain a beginner forever.Quote:
Originally Posted by Sabensohn70
Programming books do not work that way, where you see a solution for all the problems. If books were written that way, a programming book would be millions of pages long. You must use your mind and apply what concepts you've learned in solving the problem.Quote:
Originally Posted by Sabensohn70
You have a number, and you must loop n times per 100. How many times will the loop perform? The answer is n/100 (you may need to add 1 if the number is < 100). So now you loop n/100 times. Inside that loop, you print 1 star. Lo and behold, you have your output.
In your code, you took your hard-earned data, and destroyed it when you used it as a loop counter. Just create a brand new variable and use that to count the loop. All you need is a counter, it makes no sense destroying your data and using that as the counter.
You were being helped, you just didn't know it because the answer wasn't given to you. Learning to program doesn't work that way, where you are given the answer. At some point, you have to engage your mind in thinking in logical, discrete, well-defined steps. If you can't do that, then this field of study is not for you. And believe me, it has nothing to do with intelligence -- some people can think with a "programming" brain, while others can't, regardless of how intelligent they may be in other topics.Quote:
if you are not going to try to help please do not answer at all okay?
Yes, and many of them, probably sitting in your class now, could finish this assignment with no problems, or at the very least, understood immediately what Joeman and laserlight are talking about.Quote:
believe it or not there are beginners in this world
Regards,
Paul McKenzie
okay well maybe the programming world is not for me then im just a student trying to pass the class that my teacher did not teach because i asked 5/25 students in the class and the teacher did not teach this material.
Your teacher taught you about arithmetic operations, for loops, reading from standard input and printing text to standard output (the console window, in this case), right? That is enough to solve this problem, assuming that you apply what was taught.
Would you prefer the solution on a silver plater like this
or the way these members had been trying to guide you in the right direction?Code:#include <iostream>
#include <string>
int main()
{
std::string ll1l;
for(int ll(0), lll(4000),l1(0), ll1(5), l1l(100);
ll++ != ll1 && (std::cout << "Sales amount: ", std::cin >>l1);
std::cout << ll1l.append((l1 < 0 ||l1 > lll ?
(std::cout << "Try again: ", std::cin >>l1, --ll) :l1)/ l1l, '*')
<< "\n" , ll1l.clear());
}
It's your choice.
And BTW, follow this example at your own risk ;)
Lol. Nice use of the comma operator. You don't see that one everyday.Quote:
Originally Posted by potatoCode
PotatoCode, you made my day! Looks like Paul McKenzie has been cloned.
Yes, the old "give them the obfuscated answer version" trick. I've done that a few times ...Quote:
Originally Posted by potatoCode
Regards,
Paul McKenzie
@monarch_dodra:
Haha thanks. I hope I didn't break the forum rules by doing his homework
@GNiewerth:
Glad you had a good time reading it.
And I had a feeling it was done before many times :)
@Sabensohn70:
I'm sorry for turning this into something that I thought funny.
You can payback on my future post and I won't say a word.
And I think it's good that you consider yourself a beginner.
For the question you asked about using loop
Conditional Statement
A decent site that I think suitable for new learners like yourself.
C++ Basic Tutorial
A general reference site to get little deeper
Reference site (www.cplusplus.com)
And for the terms that are used in programming world that are not familiar to you
C++ Glossary
There are more,
but these are good sites for the beginners to get start on their independant study