# double and %

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• October 13th, 2003, 07:45 AM
avi123
double and %
Hi,

I have a very big number (up to 15 digits) which is stored as a double
I need to know if this number is integer or not
but % function doesn't exist for double

I wanted to do chaeck myDoubleNum%1 is not equal to 0

any suggestions?

thanks
• October 13th, 2003, 08:41 AM
Dave McLelland
Given that doubles cannot represent all values with absolute precision you might find that you assign (or enter) an integer (say 15.0) but that the double represents it as 14.999999999999.

What are you trying to do?
• October 13th, 2003, 08:49 AM
Yves M
There is a possible solution, but it has a serious caveat.

The solution is to use the function modf
Quote:

modf
Splits a floating-point value into fractional and integer parts.

double modf( double x, double *intptr );

Return Value

This function returns the signed fractional portion of x. There is no error return.
The problem with this is that the fractional part may not be exactly zero, if you have worked with the number a bit. This is a standard problem when handling floating point numbers and the usual solution is to treat everything smaller than a given epsilon as zero.

So the code could look like this:
Code:

```#include <math.h> const double epsilon = 0.00001; // you should adjust this as needed bool IsInteger(double d) {   double intpart;   return fabs(modf(d, &intpart)) < epsilon; }```
• October 13th, 2003, 08:51 AM
avi123
well

I found an ugly soloution to my specific problem

I get my gig number as a string and I have to divide it by 100 before using it.

since the string doesn't contain . (that's one of the rules)

then I simply check its last 2 chars I need them both to be 00 inorder to get an Integer

something like that:

double dMyDouble = atof(sMyTmpString.c_str());
dMyDouble /= 100;

if((sMyTmpString[14]== '0') && (sMyTmpString[13]== '0'))
{
//an integer
}
else
//not an integer

note: sMyTmpString is maximum 15 chars long and does not '.'

What do you think?
• October 13th, 2003, 08:57 AM
Yves M
Why don't you just use an integer in the first place ? Many compilers include 64 bit integers which would be enough to handle 15 decimal digits. On MS VC, the datatype in question is called __int64.
• October 13th, 2003, 09:32 AM
avi123
well I can't use int because the number may not be an Integer and then I need to treat it differently, but you gave ma another idea, check the difference between the double value to the __int64 value, meaning:

double dMyDouble = atof(sMyTmpString.c_str());
dMyDouble /= 100;

double dDiff = dMyDouble - (__int64)dMyDouble;
if(dDiff)
printf("Not an integer");
else
printf("An integer");

What do you think?
Is it better than my privious one?
• October 13th, 2003, 03:01 PM
Yves M
There may be problems with both approaches. The first one will not work correctly if the string doesn't contain exactly 14 digits. What if the string is only "12" ? The second approach suffers from the same rounding problems that Dave and myself have pointed out above.

If you really need doubles then just use my IsInteger function.
• October 13th, 2003, 04:49 PM
mwilliamson

double d = 5.1;
if( double(int(d)) == d ) // is a integer
• October 13th, 2003, 06:06 PM
Dave McLelland
Quote:

Originally posted by mwilliamson

double d = 5.1;
if( double(int(d)) == d ) // is a integer
Same representation problem. Floating point numbers may not exactly correspond with what you assign them. You cant safely do an == with a double, its not a precise representation.
• October 13th, 2003, 08:07 PM
Kheun
avi123,

Since you already captured the int/double value in the form of string, why not scan for the decimal point or '.'. If there exists non-zero value character(s) after the decimal point, the string presentation must be a double.
• October 13th, 2003, 09:44 PM
hometown
Re: double and %
Quote:

Originally posted by avi123
Hi,

I have a very big number (up to 15 digits) which is stored as a double
I need to know if this number is integer or not
but % function doesn't exist for double

I wanted to do chaeck myDoubleNum%1 is not equal to 0

any suggestions?

thanks
May I ask why it has to be 15 digits ? :(

Thanks a lot...

Regards,

-Nina
• October 13th, 2003, 10:31 PM
Joseph_R_Thomas
Re: Re: double and %
Quote:

Originally posted by hometown
May I ask why it has to be 15 digits ? :(

Thanks a lot...

Regards,

-Nina
different program have differ specifications and requirements..In what he is doin he needs to manipulate a 15 didgit number...
or he simply wants to learn how to manipulate in case of a 15 digit no...
<edit>BTW : he said UPTO 15..</edit>
• October 14th, 2003, 07:13 AM
rfmobile
Instead of modf, use floor() instead. Do use the "epsilon" approach suggested by Yves. I like using "FLT_MIN" for that purpose.

Code:

```#include <math.h> #include <float.h> int function(double dbl) { /* ... */   if (  ( dbl - floor(dbl) ) < FLT_MIN )   {     /* treat as integer. */   }   else   {     /* not integer. */   } /* ... */ }```
-rick
• October 14th, 2003, 07:33 AM
Yves M
If my memory serves me right, this doesn't work for negative numbers.
• October 14th, 2003, 08:17 AM
rfmobile
Yup, I forgot the fabs().
-rick
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