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Type: Posts; User: ulumulu
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October 1st, 2009, 07:21 AM
Well if "we" want to escape this, probably everyone have to ignore such topics as
* i am noob
* please help, urgent
and so on, and so on. All these questions are not informative, and probably its...
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September 29th, 2009, 02:28 AM
There is, but only for a fixed number size.
repeat for times
m *= 10;
m += n%10;
n /= 10;
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September 29th, 2009, 12:29 AM
Your problem lies there:
rev1 = 0
{
mod1 = num3 % 1000; // Show the reverse average to 4 digits?
num3 = num3 / 1000;
rev1 = (rev1 * 1000) + mod1;
}
you need to...
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September 27th, 2009, 01:30 PM
MagicDraw, Rational Rose, Poseidon.
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September 19th, 2009, 06:35 AM
Don't read it. Understand it :)
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September 15th, 2009, 03:47 PM
Nice.
did like this " \n\r\\"\" and worked like a charm.
Thankyou laserLight.
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September 15th, 2009, 02:41 PM
Yes. My English isn't that good. But I will try my best ;)
Simple example.
" \n\t\r"
" " \n\t\r"
And how to put it in this construction if ((strchr(", \n\r\t", chunckOfData[i])) ...
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September 15th, 2009, 02:29 PM
Hi
if ((strchr(", \n\r\t", chunckOfData[i])) ........
how to add to the string ", \n\r\t" also " type of simbol. I want to check also if chunckOfData[i] isn't ".
Thankyou in advice.
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September 11th, 2009, 03:14 PM
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September 11th, 2009, 03:00 PM
Good evening lads.
OK. Lets say I make string
std::string dataBlock;
...........................................
//Fill that string with some data...
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June 29th, 2009, 08:17 AM
To all who responded, big hugs :D
As I predicted it's not posible to code.
To JohnW@Wessex: Lettely I eat too much beens :D so fogot some pointers :blush:
To Ajay Vijay: Maybe you are right,...
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June 29th, 2009, 07:24 AM
To GNiewerth :
Well I am usein GCC 4.x compiler.
To Mybowlcut :
Somehow I knew it. But hoped that someone knows some magic tricks :D
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June 29th, 2009, 06:56 AM
Hmm. Well I tell you maybe first whay I am doing so.
it's because I may have 100 objects. Buttons, Labels, Scrollboxes and so on. And to set everytime name is a bit overkill.
Like
:
...
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June 29th, 2009, 06:01 AM
Good day.
I dont know if it is possible. But maybe there is a solution to such kind of situation.
Lets say. I have class which creates a button. and I create it.
TButton button1 = new...
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June 19th, 2009, 04:28 AM
Yes your are right :)
Cheers.
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June 19th, 2009, 04:22 AM
well chunchofData is actualy a small pease off data (block) which is parsed at the moment.
Anyway thanks for your help LaserLight. I think I found the problem.
Problem: knowledge. I am still...
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June 19th, 2009, 04:10 AM
Ok the problem is:
I have some text file. And I am parsing some data of it. So then I found the items i need. I want to hold pointers of it in vector that I could use it many times. That vector with...
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June 19th, 2009, 04:02 AM
char *tempLine;
.......................
tempLine = &chunchOfData[0];
.......................
chunchOfData[i] = '\0';
.....................
well and I want from tempLine to get adress of...
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June 19th, 2009, 03:58 AM
Oh ok. I did that and It still shows the content of X. Probably I did a mistake somewhere else. Most likely with Y in uper code. Anyway thankyou.
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June 19th, 2009, 03:09 AM
Good day.
Probably the foolish question ever, but still.
Lets say I have pointer X*and hold in it address of &Y.
How do I get the the address of Y from X. (Not the X address but Y from X)
...
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June 18th, 2009, 01:29 AM
Well relation between objects are actually weak. Anyway thankyou laserLight.
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June 18th, 2009, 12:57 AM
So you saying. that X* next will make lika a copy of new struct.
Hmm somehow I was trying to make it work like a class with (new = ) and constructor :x
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June 18th, 2009, 12:47 AM
Good day to everyone. I am a bit lost , and I hope someone could help me a bit :)
Lets say I have a struct which could have the same look of struct as itself and that child struct the same ant so...
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April 3rd, 2009, 03:20 AM
OK but if it is recursion ??? It does not create new objects. It should stay on the same address.
Does it ???
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April 2nd, 2009, 10:09 AM
void Parser::materialParsing (char *source)
{
/*
{ - New Block
, /n /t/ /r ' ' - New element
} - The end of the block
*/
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