Search:

Sounds good.. Already did this part..

I am not seeing a bitwise conversion back to a uint or int though.. Guess i can just convert it to u_long and cast it to a uint.

Also to convert the bitset...

std::bitset<8> my_bitset(value);

This seems to work just find, giving me the 8 bit representation..

And i will need it in a string now i guess since i need to flip a random bit in this bitwise...

Ok well i got it working but its giving me the 32 bit representation.

How can i take

bitset<sizeof(value) * CHAR_BIT> my_bitset(value);

and make it fixed to 8 since i know the byte value...

The reason why.. is because i have no idea what the following is doing



bitset<sizeof(value) * CHAR_BIT> my_bitset(value);



Mostly '<sizeof(value) * CHAR_BIT> ' -->> setting the size...

Could you show an example of how to use the bitwise() conversion..

I can use ints, but would rather use unsigned int,

I am not seeing a type in which i can do so for ints or uints..

And i...

Ok, let me rephrase, i need to get the 8 bit representation of that byte..

How can i get the byte value of an integer..

Let's say I need it for number '204'
The byte representation would be --> 11001100
Another example would be number '122' -- > 01111010

The minimum...

It almost seems that way, but the function actually has one more parameter am passing in that i didn't include, which determines the choice of vector to return, 4 different algorithms performed on 4...

Apparently This works:




vector< vector<int> > twoD (int columns, int rows);

int main (int argc, char ** argv)
{

No it cannot be determined at compile time..

So i guess i am doing vectors..

I will have to look up how to return a vector from a function and how to declare the function type.

I'm assuming...

I would rather not restructure the code as a whole.

IF i create global 2D arrays and just copy to them rather then passing back, would that be easier?

I have a function that has a two dimensional array i need to return:
how can i get the 2D array into another array without reading it by row and column in a loop
i.e --> the idea





int...

Thanks again everyone.. I hate getting introduced into languages where the syntax is a bit different. I am used to doing java and c#..

Also i had to change the += to just a + to append the...

Yes some of the functions below this do have the potential to throw errors..

Thanks for the intuition guys.. I am going to give it a shot right now..

I am trying to figure out how to cast the filename into a string and use the substring to remove the '.png' or whatever declaration at the end given the input to the program..

How can i cast the...

I am trying to insert a snippet of XML from a XML file, into the original file that I load.

Example:
I load XML file xmlFile1
Then load another xml file which is basically a snippet of XML that...

I thought about this also.. But unfortunately there is no such function to implement while the cell is active.

I realize now that it may not be possible to validate a cell while the user is typing in it, i.e. it's impossible to prevent the user typing more than x characters. Since, the validation only kicks...

I don't really have any code for this as it is just a simple script.. I don't use VBA often so am not too sure of the syntax. I believe there may be something to set the attributes of the entire...

Number of characters... Where



LEN(Column) ! > 20

I am trying to restrict column length for an entire column in excel.. which uses VBA..

I am not talking about the width, but the actual characters allowed in this cell..

Any help would be...

Like is being used on rows.column coming back from a table. Hence

Boolean = Row.Column Like ("RegEx")

This is working fine for all the other expressions i am using.

I just tried



Dim WeightFactor As New Regex("^([0-9]|[1-9][0-9]|100)\.[\d][\d][\d][\d][\d][\d]")
validWeightFactor = WeightFactor.IsMatch(Row.WEIGHTFACTOR)


and it seems to...

I put this in the 6.0 vb section by accident, but here is my issue:

http://www.codeguru.com/forum/showthread.php?p=1962680#post1962680

I just realized this is Microsoft Visual Basic .NET not 6.0..
I will post a link to this in that section.