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Works for me, thanks for the help.

The address of that block is myarray, not myarray[0]. myarray[0] would be 5, yes? The address of that block of memory is myarray so what exactly is &myarray... is it also the address of that block...

I like the answer but where is "c" stored (is it even stored anywhere)? I mean, it has to be stored in memory somewhere, right? This kind of goes back to my example of "a" where cout << a; prints...

Consider the following code:

int a = 5;
cout << a << " " << &a;

Obviously "a" prints out 5 and &a prints out the address of a. Now this code:

int * b = new int[2];
cout << b << " " << &b;