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Yeah, that's for find the index of the button clicked, anyway i have done a better way without using a part of the text


results[this.Controls.OfType<Button>().ToList().IndexOf((sender as...

A bit long but works


options[x].Click += delegate(object sender, EventArgs e) { results[int.Parse(this.Controls.OfType<Button>().Where(s => s.Text == (sender as...

Ok send or post it i'll try to help you

Convert the secure function to encrypt a list of byte[] instead of only one array and i can help you in code

(ps: the max value of a byte array is the Int32.MaxValue)

More info? Anyway... list.Distinct()

Probably the first array was of a different encoding, try using ASCII or Default

Ultimate edition xD


public static void Main()
{
int[,] lol = new int[3, 7]{
{1, 2, 3, 4, 5, 6, 7},
{8, 9, 10, 9, 8, 7, 11},
...

That's it


static int[] Min2d(int[,] a)
{
int rows = a.GetLength(0);
int columns = a.GetLength(1);
int[] min = new int[columns];

for...

Why? It's not c++, it's c#, an advanced object-oriented language.

Anyway...


static int[] Min2d(int[,] a)
{
int[] min = new int[a.GetLength(0)];
for (int i =...

//.....

int[,] lol = new int[3, 7]{
{1, 2, 3, 4, 5, 6, 7},
{8, 9, 10, 9, 8, 7, 11},
{5, 4, 4, 2, 1, 0, 6}};

int[] min = Min2d(lol);

...

public struct Tile
{
private const int MAXLAYERS = 4;
private const int MAXDATA = 5;
private int tileAttribute;
private int[] tileLayer;
...

Maybe i have a better solution



public static int test(int thisval)
{
Thread.Sleep(1000 * thisval);
return thisval;
}

Try in this way


foreach (ErrorButton er in this.Controls.OfType<ErrorButton>())
{
er.Reset();
}

Can you explain better(with c# examples) how you would like to use them?

Anyway for the second struct this work?


[StructLayout(LayoutKind.Sequential)]
public struct IMGSTRUCT
...

This works fine for me


void comboBox1_DrawItem(object sender, DrawItemEventArgs e)
{
if (e.Index < 0) return;

if...

Try this


do
{
Console.Write("Enter a lower case letter: ");
c = Console.ReadLine().ToCharArray()[0];
if (Char.IsLower(c) &&...