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  1. Re: Being argument, array a[2] isn't copied when calling function

    Thanks!! Now I've understood it
  2. Being argument, array a[2] isn't copied when calling function

    Hi,
    I cannot understand why the following happens, please read to the end.
    The code below outputs this:
    a[]= 00
    a[]= 10
    a[]= 10
    a[]= 10
    a[]= 11
    a[]= 11
    0.
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