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October 1st, 2003, 11:36 PM
#1
Need a Yes or a No frm you guru...
Everytime I click my mouse, a character will come up randomly, so I think if I use TextOut in which x and y are randomly chosen, I can do the job right ?
Thanks a lot...
-Nina
Last edited by hometown; October 1st, 2003 at 11:39 PM.
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October 2nd, 2003, 12:03 AM
#2
Microsoft LVP - Least Valuable Professional
Please rate this post... Pleeeeeeaaassee!!!
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October 2nd, 2003, 01:01 AM
#3
That sounds right, assuming x and y are in a proper range,
and you don't have other bugs.
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October 2nd, 2003, 01:08 AM
#4
Thank you Deniz and kochhar very much...
Regards,
-Nina
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October 2nd, 2003, 02:39 AM
#5
I usually ignore questions in which the subject does not indicate what the question is about. I might not look at your questions if the subject does not indicate it is something I am familiar with.
If I understand the question, then the answer is no.
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October 2nd, 2003, 11:48 AM
#6
This time explanation, not Yes or No
Originally posted by Sam Hobbs
I usually ignore questions in which the subject does not indicate what the question is about. I might not look at your questions if the subject does not indicate it is something I am familiar with.
If I understand the question, then the answer is no.
Yes, that sit ! My program still does not work now....That s why I come back and ask again if you have any soliution ?
And Sam why do you immediately answer NO ? Could you tell me ?
Thanks Sam....
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October 2nd, 2003, 12:17 PM
#7
I am sad because I amnot as good as you gurus...That is why I make this stupid question...If I am better I just come to help people not to ask anything....
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October 2nd, 2003, 12:43 PM
#8
Your question is not stupid, you only provide very few information...
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October 2nd, 2003, 12:55 PM
#9
Originally posted by Doctor Luz
Your question is not stupid, you only provide very few information...
In my OnLButton I wrote this code
PHP Code:
pDC->TextOut(x,y,"Diamond Rio")
with x, y are randomly chosen, but I dont know why DiamondRio doesnot appear...
Could you help me please ?
Thanks a lot...
Last edited by hometown; October 2nd, 2003 at 01:05 PM.
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October 2nd, 2003, 12:57 PM
#10
Re: This time explanation, not Yes or No
Originally posted by hometown
Could you tell me ?
Oh, so you want more than a yes or no?
You say you want "character will come up randomly". I assume you want the character to be random, not the position of the character. The x and y parameters of the TextOut function are for the position of the character, so that is why I say it won't work.
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October 2nd, 2003, 12:59 PM
#11
OnLButton() where is? a dialog? a CWnd what?
and how are x,y and pDC assigned?
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October 2nd, 2003, 01:04 PM
#12
Re: Re: This time explanation, not Yes or No
Originally posted by Sam Hobbs
Oh, so you want more than a yes or no?
You say you want " character will come up randomly". I assume you want the character to be random, not the position of the character. The x and y parameters of the TextOut function are for the position of the character, so that is why I say it won't work.
Why do you make me wait so long ????
...So sorry, I was wrong...I meant the position would be chosen randomly...Sorry
Thank you very much...
-Hometown
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October 2nd, 2003, 01:11 PM
#13
Re: Re: Re: This time explanation, not Yes or No
Originally posted by hometown
Why do you make me wait so long ????
Oh Nina, I did not realize I was making you wait. It feels good that my comments are that important to you. I hope I don't make you wait for something that truly is important. I would not do that intentionally.
Originally posted by hometown
...So sorry, I was wrong...I meant the position would be chosen randomly...Sorry
So you are of course correct that your basic algorithm is valid.
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October 2nd, 2003, 08:41 PM
#14
Re: Re: Re: Re: This time explanation, not Yes or No
Originally posted by Sam Hobbs
Oh Nina, I did not realize I was making you wait. It feels good that my comments are that important to you. I hope I don't make you wait for something that truly is important. I would not do that intentionally.
So you are of course correct that your basic algorithm is valid.
Thank you Sam very much.....
Regards,
Nina
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