Reverse number program

[soopa1]

I need a lil help. I'm new to C++ and, I have to write a function that takes an integer as a perameter and returns the number with its digits reversed. ex. 5678
would return 8765. I also have to use at least 2 more functions to read and print the result. I need a little nudge in the right direction. This is what I have so far, and I'm 90% sure it is completely wrong! lol


#include<iostream>

using namespace std;

int reverseDigit(int num)
void print(int num)
int read();

int main()
{
int num= read();
print(int(num));
return 0;
}
int read()
{
int a
cout<<"Enter a number"<<endl;
cin>>num;
return a;
}

int reverseDigit(int num)
{
int
while(num>0)
{
num = num % 10; //// This is where I know I'm waaaay off!
num = num / 10;
num= num - 2;
}
}


return 0;

[HighCommander4]

I suggest converting the number to an std::string using the stringstream classes, reversing the order of characters in the string using a simple loop, then converting the string back into numeric form. If you haven't worked with strings or stringstreams yet, post back and I will help you write some code that would do this.

[soopa1]

I've never used those before. I've just started getting into predefined and user defined functions, and for the program I can only use those types of functions.

[HighCommander4]

I've never used those before. I've just started getting into predefined and user defined functions, and for the program I can only use those types of functions.

I've yet to hear of functions that are neither predefined nor user-defined...

Anyways, an example code would look like this

#include <iostream>
#include <string>        // for std::string
#include <sstream>    // for stringstreams
using namespace std;

string number_to_string(int number);
int string_to_number(string str);
string reverse_string(string str);

int main()
{
    int num = 5678;
    string str = number_to_string(num);
    string reversed_str = reverse_string(str);
    int new_number = string_to_number(reversed_str);
    
    return 0;
}

string number_to_string(int number)
{
    string result;
    ostringstream ostr;
    ostr << number;
    result = ostr.str();
    return result;
}

int string_to_number(string str)
{
    int result;
    istringstream istr(str);
    istr >> result;
    return result;
}

string reverse_string(string str)
{
     int i, j;
     char temp;
     for (int j = 0; i < str.size(); j < i; i--, j++)
     {
          temp = str[i];
          str[i] = str[j];
          str[j] = temp;
      }
      return str; 
}

[soopa1]

I've never used those before. I've just started getting into predefined and user defined functions, and for the program I can only use those types of functions.

Yeah..I realized that after I typed it..lol


The thing is I can't use sstream and stringstream,because we have not done those in class. I can kinda understand where you are coming from though.

[soopa1]

Let me post the full question HighCommander4.

Write a function, reverseDigit, that takes an integer as a perameter and returns the number with its digits reversed. For example, the value of reverseDigit(12345) is 54321. You should use 2 more functions to read and print the result.

I think my main probelm is this section of my code:

int reverseDigit(int num)
{
int val
while(num>0)
{
num = num % 10; // missing some steps
num = num / 10;
num= num - 2;
}



return val;
}

void out(int num)
{

cout<<num<<endl;
}

[Paul McKenzie]

You need to keep a sum in your function. Right now, you are destroying your original number right at the very first iteration of the loop (use a debugger to see the steps that are happening when you call your reverseDigits function).

If you don't know how to use a debugger, now is the time to learn.

First, look at the following for 8765:

(Iteration 1)
0 * 10 + 5 = 5

(Iteration 2)
5 * 10 + 6 = 56

(Iteration 3)
56 * 10 + 7 = 567

(Iteration 4)
567 * 10 + 8 = 5678

return 5678

Do you see the pattern? The first number in the equations above is the "current sum". It always starts at 0 and is accumulated in the while loop. Each "subanswer" is the new sum to be used in the next equation.

I didn't write the while loop, but hopefully you see what is going on to do this correctly. You were somewhat on the right track with the modulus operator, but you needed to do a little bit more work to get the correct calculations for the number.

Regards,

Paul McKenzie

[mop]

#include <iostream>
using namespace std;

// Prototypes
void rev(unsigned long N, ostream& out);

int main()
{
  const unsigned long value = 8951;

  cout << value << endl;
  rev(value, cout); cout << endl;

  return 0;
}

// Recursive Reverse Digit Function
void rev(unsigned long N, ostream& out)
{
  if (N > 0)
  {
    out << N % 10;
    rev(N / 10, out);
  }
}

[Kheun]

Based on Paul's excellent suggestion...

#include <iostream>
using namespace std;

int reverseDigit(int num)
{
	int result = 0;

	while(num > 0)
	{
		result = result*10 + num%10;
		num /= 10;
	}

	return result;
}

int main()
{
	int amount = 12345;
	cout << amount << endl;
	cout << reverseDigit(amount) << endl;	
}

[Elrond]

The main error was to work on only one variable instead of using at least one additional variable to make the reversing.