Polymorphism .. override

[GoDaddy]

When you override a virtual function of a base class .. do you have to call the base class method ? Always ?

I've tested with Visual Studio .. as i type override .. it automatically call the base class virtual function.

Why ???? is it like that ?

I mean ... whatever the implementation of the virtual function of the base class .. that implementation will be called ... but why should i ? I want my own implementation to be used only ....

Thanks,

[GoDaddy]

i guess i could take it off, but i've seen alot of examples doing it, calling the base method in the override implementation. But why?

[Mattrang]

Can virtual be protected ?

[GoDaddy]

Can virtual be protected ?

In C# there's no such thing as access modifier on inheritance .. not like c++.

I know in c++ youd do class A : public B

but in C# its

class A : B

EDIT : OH sorry i think you meant if you can declare a virtual method as protected ? The answer to that is NO.

[Rolander]

Can virtual be protected ?

If protected, then no override is allowed

[Emiene]

When you override a virtual function of a base class .. do you have to call the base class method ? Always ?

I've tested with Visual Studio .. as i type override .. it automatically call the base class virtual function.

Why ???? is it like that ?

I mean ... whatever the implementation of the virtual function of the base class .. that implementation will be called ... but why should i ? I want my own implementation to be used only ....

Thanks,

Your inheritance hierarchy might have some problem

class Base{
    public virtual void funfoo(){
        Console.WriteLine("funfoo Base");
    }
}

class Derive1 : Base{
    public override void funfoo(){
        Console.WriteLine("funfoo Derive1");
    }
}

class Derive2: Derive1{
    public override void funcfoo(){
        Console.WriteLine("funfoo Derive2");
    }
}

class AfterAll{
    public static void Main(string[] args)
    {
        Base b  = new Base();
        Base d1 = new Derive1();
        Base d2 = new Derive2();
              
        b.funfoo(); //Only this one calls the base class
        d1.funfoo();
        d2.funfoo();
        
        
        Derive1 d01 = new Derive1();
        Derive2 d02 = new Derive2();
        
        
        d01.funfoo();
        d02.funfoo();
    }
} 

[GoDaddy]

I meant that when i try to override a virtual function of a base class, Visual studio will do a autocomplete like this

public override void foo()
{
     base.foo() //This part is generated automatically by VS.NET .. but why???? do i needed?
}

[Emiene]

I meant that when i try to override a virtual function of a base class, Visual studio will do a autocomplete like this

public override void foo()
{
     base.foo() //This part is generated automatically by VS.NET .. but why???? do i needed?
}

Ohhh...,
I guess it is based on the understanding of object architecture, MS people may think it is a base class ctor that should be auto-generated during coding stage to, at the same time, remind end-users or coders what is overriden. It may seem to be irrelevent to many people but such a feature doesn't bug the application anyway.
Auto-generating code on coding editors is not new at all, but other people may offer you other ideas on how such code snip is auto-created if you still want to understand..

[GoDaddy]

Thanks

So i don't need it ....

[jhammer]

Can virtual be protected ?

Yes it can!!!
For example:

class Base
{
	protected virtual  void foo()
	{
		
	}
}

class Derived:Base
{
	protected override  void foo()
	{
		base.foo ();
	}

}

This code works.