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December 8th, 2012, 07:46 PM
#1
How To Open File And Load Contents Into A Variable
Hi,
in my PHP webpage I specify 3 files, like:
Code:
$first_file = $_POST["one"];
$second_file = $_POST["two"];
$third_file = $_POST["three"];
then I have a JS fuction, that in some points, needs to open each file and store the data of each file into a variable. My questions are 2:
First, how do I save all data of each text file into a JS variable?
Second, the part of the Js function which has these variables looks like this:
Code:
series:
[
{
name: 'ONE',
color: 'blue',
data:
[
HERE WE SHOULD PLACE ALL DATA FROM FILE 1
]
},
{
name: 'TWO',
color: 'yellow',
data:
[
HERE WE SHOULD PLACE ALL DATA FROM FILE 2
]
},
{
name: 'THREE',
color: 'red',
data:
[
HERE WE SHOULD PLACE ALL DATA FROM FILE 3
]
}
]
Can you please help me, how I can put the data of each file into the correct place? I am new to JS and came across a helpful snipet of code, but I do not know how I can place my data inside the JS code so as to use them.
Thanks a lot!
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December 12th, 2012, 02:43 PM
#2
Re: How To Open File And Load Contents Into A Variable
Just echo the PHP content in the middle of the JavaScript.
PHP Code:
<script type="text/javascript"> var jsVariable = "<?php echo $phpVariable; ?>"; </script>
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