C++ ascending and descending???

[Reon]

IN c++... I get output on 10 numbers after i entered sufficient data, i want to make that numbers either in ascending or in descending orders ..

here is my code but is asks for 10 numbers to print thats ok.. but i want to displayed all the numbers in different locations and want to print like ... number is 2.4.7,9,etc in ascendin orders....


#include<iostream.h>
#include<conio.h>
class loops
{
int num;
int times;
public:
void display()
{
times=0;
for(;;times++)
{
if(times>=10)
{
break;
}
cout<<endl<<"Enter a number";
cin>>num;
num=num;
}
}
void output();
};
void loops:utput()
{
num=0;
for(;;num++)
{
if(num>=10)
{
break;
}
cout<<endl<<"Number is :"<<num;
}
}
void main()
{
clrscr();
loops l1;
l1.display();
l1.output();
getch();
}

Would anybody pls know help me to solve this...

[laasunde]

Please show us your code.

[sreehari]

There are a lot of sortng methods. An easy and straigh forward one would be

smallest = number 1
outerloop
{
    inner loop
   {
           if number2 > smallest then
                   smallest  = number2
          else 
                   do the same with next number ( number3..4..and so on ) in innerloop
    }
        print smallest
        exclude the first smallest number 
        return to outerloop to find second smallest
}

[cilu]

Search the web for sorting methods:

• bubblesort
• shakesort
• shellsort
• quicksort
• radix sort

Well, you can always use std::sort from <algorithms>

int array[10]; // fit it in

std::sort(&array[0], &array[9]);

or

std::vector<int> array; // fill it in

std::sort(array.begin(), array.end());

To decide the order, ascending or descending, use a boolean predicate as the third parameter. Look in MSDN for the std::sort documentation.

[Mybowlcut]

Cilu you're too fast!

My suggestion is to use vectors! Here's my suggestion's code anyways...

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
    vector<int>::const_iterator iter;
    vector<int> listOfNums;
    
    for(int i = 0; i < 10; ++i)
    {
        cout << "\n\n"<<i + 1<<". Enter a number: ";
        cin >> number;
        listOfNums.push_back(number);
    }
    
    sort(listOfNums.begin(), listOfNums.end());
    
    for(iter = listOfNums.begin(); iter != listOfNums.end(); ++iter)
    {
        cout << *iter << endl;
    }
    
    return 0;
}

[exterminator]

As for the predicate, you can use less<T> (which I think is the default) and greater<T> for std::sort.

[Reon]

I'm not familiar with vector and so.. i only know conio,iostream & fstream..i s there any probability to complete the program in that way....

Cilu you're too fast!

My suggestion is to use vectors! Here's my suggestion's code anyways...

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
    vector<int>::const_iterator iter;
    vector<int> listOfNums;
    
    for(int i = 0; i < 10; ++i)
    {
        cout << "\n\n"<<i + 1<<". Enter a number: ";
        cin >> number;
        listOfNums.push_back(number);
    }
    
    sort(listOfNums.begin(), listOfNums.end());
    
    for(iter = listOfNums.begin(); iter != listOfNums.end(); ++iter)
    {
        cout << *iter << endl;
    }
    
    return 0;
}

[Reon]

i only know conio,iostream & fstream..i s there any probability to complete the program in that way....

Cilu you're too fast!

My suggestion is to use vectors! Here's my suggestion's code anyways...

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
    vector<int>::const_iterator iter;
    vector<int> listOfNums;
    
    for(int i = 0; i < 10; ++i)
    {
        cout << "\n\n"<<i + 1<<". Enter a number: ";
        cin >> number;
        listOfNums.push_back(number);
    }
    
    sort(listOfNums.begin(), listOfNums.end());
    
    for(iter = listOfNums.begin(); iter != listOfNums.end(); ++iter)
    {
        cout << *iter << endl;
    }
    
    return 0;
}