getting average!!

[blufr321]

hi im stuck.
lets say i have
int count =6;
and make and array of
float n[6]={1,2,3,4,5,6},total,average;
and i want it to add all the numbers up
How would i do this in a loop?
NOT this way
n[0]+n[1]+n[2]+.... then /count

[g_gili]

float sum = 0;
float n[6]={1,2,3,4,5,6}

for( int i = 0; i<count; ++i)
{
    sum += n[i];

}

float average = sum/count;

Good luck!

Gili

[blufr321]

thnx its working fine now

[cilu]

Or, with the use of accumulate

#include <algorithm>

float n[6]={1,2,3,4,5,6}
float sum = std::accumulate(&n[0], &n[5], 0);
float avg = sum / 6;

[Pravin Kumar]

Hello,

It is advantageous to use STL where the size of the array is bound with the data itself. Here is a sample code to evaluate the average of a vector array.

float average(std::vector<float> array)
{
	float sum = 0;
	for (int count = 0; count < array.size(); count++)
		sum += array[count];
	return sum / array.size();
}

Regards,
Pravin.

[cilu]

Hello,

It is advantageous to use STL where the size of the array is bound with the data itself. Here is a sample code to evaluate the average of a vector array.

float average(std::vector<float> array)
{
	float sum = 0;
	for (int count = 0; count < array.size(); count++)
		sum += array[count];
	return sum / array.size();
}

Regards,
Pravin.

I suggest passing the vector by reference to avoid making a useless copy (especially if the vector holds many elements).

[Philip Nicoletti]

Or, with the use of accumulate

#include <algorithm>

float n[6]={1,2,3,4,5,6}
float sum = std::accumulate(&n[0], &n[5], 0);
float avg = sum / 6;

1) accumulate is in <numeric>
2) the "end()" iterator has to be one past the last element

float sum = std::accumulate(&n[0], &n[6], 0); // or (n,n+6,0.0f)
float avg = sum / 6;