g++ err: linker input file unused because linking not done

[tutorcgs]

I already have the compiled object files *.o, but when I try to create executable (link object files) it outputs following error with each include, library, and object files and no executable is created.

g++: -lsomelib: linker input file unused because linking not done
g++: file.o: linker input file unused because linking not done
...

Following command is executed from the Makefile:
g++ -g -DLINUX -o $(EXE) $(LIBDIR) *.o

Any idea what might be causing this error? I have include all files and libraries which I used during compiling it which was successfull.

Please help.

Thanks

[treuss]

Either there is something wrong with your binutils (i.e. your linker) or with your Makefile. It would help, if you posted the command that g++ is trying to execute, i.e. what $(EXE) and $(LIBDIR) are expanded to.

[dude_1967]

Remember that GNU make is not Unix.

g++ -g -DLINUX -o $(EXE) $(LIBDIR) *.o

I do not believe that GNU make understands the wildcard, *.o. I think that you must create a file object list which contains each of the object files and link this list to create the executable file.

I would also recommend placing the object file list befor the -o directive because this is more intuitive.

Sincerely, Chris.

[dude_1967]

I just looked at your question again and realized that you are not using GNU make. Sorry.

The response is still valid. I believe that g++ command line does not understand the wildcard. An explicit file list is needed.

Try to create an explicit file list.

Sincerely, Chris.

[tutorcgs]

Thanks everyone for helping!

I am using GNU make and sending the list of each object file. I just used the wildcard here just to generalize what I was doing.

I am able to link the files manually now.

From make file it is some how automatically putting -E flag for g++ which is causing not to link. My Makefile doesn't have the -E flag but I am not sure where it is getting from.

Any ideas how Makefile is getting this -E flag automatically?

Thanks

[tutorcgs]

It links and creates the executable. I was using $(CPP) for link command in my Makefile which wasn't define in Makefile. Now I am using the variable which is define and it resolved the link and g++ -E mystery issue.

I hate copy/paste!

Thanks all for your help.