Save HEx output to Variable

[Neon612]

I've been trying to teach myself C++ over the years and here is another shot at it.

I know how to convert a charcter to its ASCII equivilent(sp?) and then to it's hex equivilent and print the hex number out.

Example:

cout << hex << int(line[a]);

But I want to save the hex output to a variable. I'm not sure whether it should be a string or an int, or even how you go about coding it.

My Guesses:
out_line[a] = hex(int(line[a]));
out_line[a] = hex << int(line[a]);

I do have a background in Visual Basic (megar background, started at age 7, am now 18), and could do this real easy in VB but I want to learn another language so I'd figured I'd give it a shot.

[anantwakode]

Hi,

unless and until you store value as a string , all values are stored in the form of binary.

int i = 0x05; //hex
i=5; //decimal
i=05;//octal

value of this no is 5 i.e 0101.

so value is the same only representation and symbol changes as per the no. system. while displaying you need to take care of the no system and its representation.

-Anant

[Neon612]

I'm sorry but I'm completely new at this. I've been trying to find books to get a little reading done on C++ but haven't had much luck.

You are basically saying that cout << hex << int(line[a]) is returning an integer value, and I need to convert it to a char/string value in order to use it?

[Paul McKenzie]

I know how to convert a charcter to its ASCII equivilent(sp?)

There is nothing to convert.

#include <iostream>
using namespace std;

int main()
{
   char c = 'A';
   if ( c == 65 )
        cout << "This is equal to 65\n";
  if ( c == 0x41 )
        cout << "This is equal to 0x41\n";
}

You will see that both cout statements are executed, since an 'A' is equal to 65 or 0x41. Characters are already numbers -- the representation when you output the character is what is different.

If you want to store the output into a string, use stringstreams or the unsafe sprintf() function.

Regards,

Paul McKenzie