Help with assigning Array Size

[oatmeal1201]

What the heck is the problem?

code:

// Determine the total number of employees
inputEmployees = JOptionPane.showInputDialog(null, "How many employees do you have?");
EMPLOYEES = Double.parseDouble(inputEmployees);

// Create an array to hold employee salaries.
double[] salaries = new double[EMPLOYEES];



The error I'm getting is Salaries.java:33: incompatible types
found : java.lang.Double
required: int

Why does it say required int? I made it Double.

[oatmeal1201]

Thanks, I took a different route and have another question.

I need to Display the Names and Salaries of all Employees that are higher than the Average. I have included the code which shows how to display the highest salary of them all but am having trouble figuring out how to display this for each employee.



public class Salaries
{
public static void main(String[] args)

{
// Create a Scanner object to read input.
Scanner keyboard = new Scanner(System.in);


String name;
String input;
double salary;
String inputEmployees;
double number;
int EMPLOYEES;

// Determine the total number of employees
System.out.print("How many employees do you have?");
EMPLOYEES = keyboard.nextInt();

// Create an array to hold employee names.
String[] names = new String[EMPLOYEES];

// Create an array to hold employee salaries.
int[] salaries = new int[EMPLOYEES];

// Get each employee's name.
for (int index = 0; index < names.length; index++)
{
System.out.print("What is the employee name for employee number " + (index + 1) + ": ");
names[index] = keyboard.next();
}


// Get each employee's salary.
for (int index = 0; index < salaries.length; index++)
{
System.out.print("What is the employee salary for employee number " + (index + 1) + ": ");
salaries[index] = keyboard.nextInt();
}


// Display the average
double total = 0; // initialize accumulator
double average; // Will hold the average
for (int index = 0; index < salaries.length; index++)
total += salaries[index];
average = total / salaries.length;
System.out.println("The average is :" + average);


// Display the highest salary
int highest = salaries[0];
for (int index = 1; index < salaries.length; index++)
{
if (salaries[index] > highest)
highest = salaries[index];
}

[dlorde]

What the heck is the problem? ...
Why does it say required int? I made it Double.

The compiler is complaining about you trying to assign a double (the number of employees input) to an int (EMPLOYEES). There's no reason to make the number of employees a double - can you have .35 of an employee?

In the particular is contained the universal...
J. Joyce

[dlorde]

I need to Display the Names and Salaries of all Employees that are higher than the Average. I have included the code which shows how to display the highest salary of them all but am having trouble figuring out how to display this for each employee.

Can't you store the average salary, then run through all the employee salaries printing out those that are larger?

[In a programming language] Simple things should be simple and complex things should be possible...
A. Kay