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  1. #1
    Join Date
    Feb 2009
    Posts
    16

    for loop stop condition help

    hallo, I am new to this forum so I hope this isn't a trivial question. I have written a simple program to calculate the stopping distance of a vehicle and was wondering how I stop the for loop when the function gets to 0 or less. I was thinking maybe I could assign a character to the solution "s" with an if statement. Like s=NEG if s<=0 then using that as the stop condition.
    Any help would be appreciated.

    Code:
    #include <iostream.h>
    #include <iomanip.h>
    float f(float, float, float); //function prototype
    int main(){
            float v,u,g,m,h,s[100],T[100];
            int i, n;
            cout << "values of v,u,m,n,h are (n must be < 100) \n";
            cin >> v >> u >> m >> n >> h;
            s[0] = 0;
            T[0] = 0.5*m*v*v;
            for(i = 0; i<n ;i++){//this is the euler loop
                    T[i+1] = T[i] + h * f(u,m,g);
                    s[i+1] = s[i] + h;
            }
            //set headings for table and then print table
            cout << setw(0) << "s (Distance)" << setw(20) << "T (Kinetic Energy)" << "\n";
            cout.setf(ios :: fixed);
            for(i = 0; i <= n ; i++)
            cout << setprecision(0) << setw(7) << s[i]
                 << setprecision(0) << setw(20) << T[i] << endl;
            return 0;
            }
            //this is the function f of the differential equation
            float f(float u, float m, float g){
                    g = 9.8;
                    return -g*m*u;
            }
    Last edited by Marc G; February 12th, 2009 at 01:48 PM. Reason: Added code tags

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