passing pointers of array to function

[madmaze]

Hello everyone,
ive been googleing this all day and havent found an answer yet.
i want to create an array in int Main() and then pass a pointer referencing the
array to a function to fill it.
This is how far i have gotten:

int main(void)
{
	test();
	float dat[1000];
	readnprint(&dat[0]);
       /*
         other code her
        */
}

void readnprint(float *base_ptr)
{
    //init ifstream etc etc..
         float addr=base_ptr;
	while (!ins.eof())
	{
		ins>>x;
		float f;
		if(from_string<float>(f, string(x), dec)) //parse float?
		  {
			addr=(base_ptr)+(sizeof(float)*cnt)           //steps through array by sizeof(float)
			*(float)addr=f;  //have this assign the value to memory location (problem)
		  }
		  else
		  {
			cout << "from_string failed" << endl;
		  }
		cnt++;
	}
	ins.close();
}

im sure im just tired and not thinking right, does anyone have a better/working way of doing this?

thanks

-maze

[Plasmator]

im sure im just tired and not thinking right, does anyone have a better/working way of doing this?

Why are you working with arrays? A proper container (e.g., std::vector) is more robust and safer.
As for the other part of your problem, this is easily solvable with std::generate and a functor.

[_Superman_]

This is one way of doing it.

void main()
{
   float dat[1000];
   readnprint(dat, 1000);
}

void readnprint(float* base_ptr, int size)
{
   for (int i = 0; i < size; ++i)
   {
      base_ptr[i] = i;
   }
}

[laserlight]

This is one way of doing it.

Note that void main() should be int main(), as in madmaze's original example.

[madmaze]

not sure what i was thinking last night.. simply passing by ref is the easiest..
thanks for the responses =)