October 3rd, 2009, 12:37 PM
I have a problem in c++ where I must be able to enter a maximum of 100 values. I must be able to cancel the input whenever I want. And when the input is finished a menu will show up. I'll be using vectors and loops.
How do I:
1. calculate the highest value?
2. How do I calculate the lowest value?
3. How do I calculate the mean?
4. How do I list all of the numbers in one column with one decimal right under each other.
using namespace std;
const int value=100;
double middle, highest, lowest, sum = 0;
double counter[value + 1];
int i, val;
for (i=1; i<=value; i++)
cout << "Enter some values: ";
while (cin >> value)
cin >> counter[i];
middle = sum / value;
cout << "1. highest" << endl;
cout << "2. lowest" << endl;
cout << "3. middle" << endl;
cout << "4. Lista" << endl;
cout << "5. end" << endl;
cout << endl << "Välj: ";
cin >> option;
Have I done anything wrong so far?
Any help appreciated!
October 3rd, 2009, 01:05 PM
Well, I don't see any vectors there, just an array.
You aren't going to have much luck trying to read from cin into a const int (value).
Why are you ignoring counter?
What is the condition under which input ends with fewer than 100 numbers?
main() should return int.
I don't see a loop to take you back to the menu after executing each option.
"middle" probably isn't the best variable name for a mean, since it brings to mind a median instead.
Tasks (1), (2), and (3) are pretty trivial math operations, you should be able to write each in 3-4 lines. If you're allowed to use the STL algorithms, each becomes one line. I'm not sure what you mean by (4).
October 3rd, 2009, 01:17 PM
Can you correct it for me?
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