calling a function within a function

[Fezzy]

Hello all i am currently working on an assignment and I am almost done with it. I'm having a bit of a hard time understanding the calling of a function within a function.

Here is some background to the program. It has generated randomly the phone number, age, credit card number, and has giving each employee a 1 (for secure) or 0 (for unsecured). I bascally have two functions print_secure and print_all. If the information is not secure it will display everything and if it is, it will display certain items.

Here is what I have so far.

void CustomerData::print_all()
{
  int empNo;
	cout << "Please enter the Employee Number: ";
	cin >> empNo;
	
	if (0 > empNo || empNo > 49) // checks to make sure that user entered value is within the limit [0 .. 49] 
		{
		cout << "The Employee Number entered is out of bound. Please try again.\n";
		return;
		}
	
	//Employee details are printed below
	cout << "\nEmployee details\n";
	cout << "----------------\n";
	cout << "Employee Number: " << employees[empNo].empNo << "\n";
	cout << "Employee Security Preference: " << employees[empNo].security_preference << "\n";
	cout << "Age: " << employees[empNo].empAge << "\n";
	cout << "Phone Number: " << employees[empNo].empphone << "\n";
	cout << "Credit Card Number: " << employees[empNo].empCCNo << "\n";
	cout << "\n\n";
}


/*void CustomerData::print_secure()
{
 	//Employee details are printed below
	cout << "\nEmployee details\n";
	cout << "----------------\n";
	cout << "Employee Number: " << employees[empNo].empNo << "\n";
	cout << "Employee Security Preference: " << employees[empNo].security_preference << "\n";
	cout << "Employee Age: " << employees[empNo].empAge << "\n";
	cout << "\n\n";
}*/

Since I don't want a classmate taking my code I only posted what I think is the main part I need help with.

I was thing of putting an if statement in void CustomerData:: print_all() to reference void CustomerData:: print_secure() but I don't have a clue as how to reference it. Could someone offer some advise?

[MrViggy]

I don't understand what the question is...

Viggy

[Skizmo]

I don't understand what the question is...

Viggy

He is asking us how he should remove a few cout-lines and call print_secure instead because they actually print the same.

[Fezzy]

Sorry mate.

I want to create an if statement in the print_all function that says if "security_preference" has a 1 then us the "void CustomerData:: print_secure()" function as the output. How can I go about this?

[Skizmo]

Sorry mate.

I want to create an if statement in the print_all function that says if "security_preference" has a 1 then us the "void CustomerData:rint_secure()" function as the output. How can I go about this?

See my last post, and after that you need to create a if to check if you need the print the extra info.

[CoolPG]

Sorry mate.

I want to create an if statement in the print_all function that says if "security_preference" has a 1 then us the "void CustomerData:: print_secure()" function as the output. How can I go about this?

Why cant you think of doing that condition check in the place where you intend to call print_secure() or print_all()?

i mean like,

CustomerData cd;
if( security_preference == 1 )
         cd.print_secure();
else
         cd.print_all();