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December 31st, 2009, 08:59 AM
#1
Finding Duplicate Files
Is there an easier way to find duplicate files?
Code:
import java.io.*;
public class Test {
public static void main(String[] args) throws Throwable {
System.out.print(duplicate(new File("C:\\Users\\Me\\Desktop\\4-01 Living the Dream.avi"),
new File("C:\\Users\\Me\\Desktop\\4-01 Living the Dream - Copy.avi")));
}
public static boolean duplicate(File f1, File f2) throws Throwable {
FileInputStream fis1 = new FileInputStream(f1),
fis2 = new FileInputStream(f2);
byte[] ba1 = new byte[fis1.available()],
ba2 = new byte[fis2.available()];
if (ba1.length == ba2.length) {
fis1.read(ba1);
fis2.read(ba2);
for (int i = 0; i < ba1.length; i++) {
if (ba1[i] != ba2[i]) return false;
}
return true;
}
return false;
}
}
Is this seriously the quickest way? I notice some redundancy when you read the FileInputStream into the byte array, and then check each byte. Is there a way to read the file byte-by-byte and check it on-the-fly? It would replace the byte array, to just one byte variable.
Last edited by Nim; December 31st, 2009 at 09:45 AM.
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