LINQ - Calculate average and standard deviation in one go

[mrbomb]

I have a list with values:
List<double> values = new List<double> {4,5,7,7,8,98,1,3,4,2,2,4,5,5,6,7,8,5,3,2,9,4,5,6,7,8};

I want to get:
the average = sum(values)/n
standard deviation = sqrt( (sum(values^2) - n*average)/(n-1) ) as quickly as possible (I need to do this for many many lists)

Is it possible to let the computer iterate only once over this list to get:
- the sum of the values
- the sum of the values squared?

[mariocatch]

May have missed the formula's order of operations, but here's my attempt at it:

namespace MathHelp
{
    using System;
    using System.Collections.Generic;

    class Program
    {
        static void Main(string[] args)
        {
            List<double> values = new List<double> { 4, 5, 7, 7, 8, 98, 1, 3, 4, 2, 2, 4, 5, 5, 6, 7, 8, 5, 3, 2, 9, 4, 5, 6, 7, 8 };
            double average = 0;
            double total = 0;
            double deviation = 0;
            for (int i = 0; i < values.Count; i++)
            {
                total += values[i];
                if (i == values.Count - 1)
                {
                    average = total / values.Count;
                    deviation = Math.Sqrt(((Math.Pow(total, 2)) - (values.Count * average))) / values.Count - 1;
                }
            }

            Console.WriteLine("Average: {0}", average);
            Console.WriteLine("Deviation: {0}", deviation);
            Console.ReadLine();
        }
    }
}

[mrbomb]

There's no need for LINQ I see. I converted it into this:

            mean = 0;
            double stdDev=0;
            foreach(double v in dataList) {
                mean += v;
                stdDev += v*v;
            }

            mean /= N;
            stdDev = Math.Sqrt((stdDev - N * mean * mean) / (N - 1));