Problem with Arrays and comparisons

[SamstaUK]

I am trying to run this code:

@row1 = ('1','2','4','5','6','8','9');


for($i=1; $i<=9; $i++){
	if(@row1 =~ /$i/){
		print "$i worked\n";
		}
	}

I idea is that it prints:
1 worked
2 worked
4 worked etc...

However, the only thing it outputs is '7' worked, which I think is because the array is 7 elements long?

Without introducing another loop(because that will make my final task a lot harder), how can I see if an element exists in an array? I've tried using if(exists($row1[$i])){} but with no luck.

How can I get the desired output?

Any help will be greatly appreciated

--Sam Kennedy

[skyfe]

In PHP it would be:

if(in_array($i, $row1)) 

To check if a value is inside the array, and:

if(array_key_exists($i, $row1)) 

To check if the key exists inside the array.

But as Im not sure which language this was meant to be for...

[SamstaUK]

Whoops sorry, it's in perl. I found out I simply needed to put the array in quotes to get the contents rather than the length.

Sorted

[dsp8]

Of course you could keep it in php:

#!/usr/bin/php -q
<?php
$row = array('1','2','4','5','6','8','9');
for($i=1; $i<=9; $i++) {
if($row[$i] != $i){
print "$i worked\n";
}
}
?>