[RESOLVED] setbase not setting the base for cout
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Thread: [RESOLVED] setbase not setting the base for cout

  1. #1
    Join Date
    Mar 2010
    Posts
    7

    [RESOLVED] setbase not setting the base for cout

    I'm having trouble understanding why this code doesn't work. I am copying almost verbatim from msdn help for the setw iomanip library function. It should set the base for output, but it isn't.

    Code:
    #include <iostream>
    #include <iomanip>
    
    using namespace std;
    
        int paws;
        int base = 10;
    
        const double      d1 = 16.0;
        const double      d2 = 256.0;
        const double      d3 = 1024.0;
        const double      d4 = 4096.0;
        const double      d5 = 65536.0;
    
    
    void printBases(double input)
    {
        cout << "input: " << input << ", oct:" << setbase(8) << input << ", hex:" << setbase(16) << input << "\n";
    }
    
    void DisplayLongs( )
    {
       cout << setbase(10);
       cout << endl << "setbase(" << base << ")" << endl;
       cout << setbase(base);
       cout << "l1 = " << d1 << endl;
       cout << "l2 = " << d2 << endl;
       cout << "l3 = " << d3 << endl;
       cout << "l4 = " << d4 << endl;
       cout << "l5 = " << d5 << endl;
    }
    
    int main()
    {
    
    
        printBases(d1);
        printBases(d2);
        printBases(d3);
        printBases(d4);
        printBases(d5);
    
        base = 16;
        DisplayLongs();
        
        base = 8;
        DisplayLongs();
        
        base = 10;
        DisplayLongs();
    
        return (EXIT_SUCCESS);
    }


    output:

    C:\My Programs\pretest3\Debug>pretest3
    input: 16, oct:16, hex:16
    input: 256, oct:256, hex:256
    input: 1024, oct:1024, hex:1024
    input: 4096, oct:4096, hex:4096
    input: 65536, oct:65536, hex:65536

    setbase(16)
    l1 = 16
    l2 = 256
    l3 = 1024
    l4 = 4096
    l5 = 65536

    setbase(8)
    l1 = 16
    l2 = 256
    l3 = 1024
    l4 = 4096
    l5 = 65536

    setbase(10)
    l1 = 16
    l2 = 256
    l3 = 1024
    l4 = 4096
    l5 = 65536

    C:\My Programs\pretest3\Debug>


  2. #2
    Join Date
    Apr 1999
    Posts
    27,424

    Re: setbase not setting the base for cout

    Quote Originally Posted by MattInSD73 View Post
    I'm having trouble understanding why this code doesn't work. I am copying almost verbatim from msdn help for the setw iomanip library function. It should set the base for output, but it isn't.
    Change those doubles to longs. What are your results?

    Similarly, what if you changed one of the double values to 16.5 instead of 16.0? What would you have expected your output to be?

    Regards,

    Paul McKenzie
    Last edited by Paul McKenzie; March 30th, 2010 at 11:11 PM.

  3. #3
    Join Date
    Mar 2010
    Posts
    7

    Talking Re: setbase not setting the base for cout

    I assumed that the doubles would get converted to the proper base, but apparently cout and setbase don't play that well enough together as to accept a non-integral type. Luckily, I don't need the fractional values, so I can truncate with a cast to long.

    Thanks for the help!

    Code:
    void printBases(double input)
    {
        cout << setbase(10) << "input: " << (long) input << ", oct:" << setbase(8) << (long) input << ", hex:" << setbase(16) << (long) input << "\n";
    }

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