Code Help Function

[twogreenarrows]

Problem: how many small squares can you put into a rectangle
Formula: i'll get the area of the rectangle and divide it by the area of the square.
CODE:

#include <stdio.h>

int areaSquare(int nSide){

int nAreaS;
nAreaS=(nSide*nSide);
return (nAreaS);
}

int areaRectangle (int nLength, int nWidth){

int nAreaR;
nAreaR=(nLength*nWidth);
return (nAreaR);
}

main(){
float numberSquares;
numberSquares=areaRectangle()/areaSquare();

printf("The Number of Squares:%.2f", numberSquares);
getch();
}


i used getch(); so i can see my visual output,

PROBLEM: too few arguments on areaRectangle and areaSquare on main.
if i did a mistake please tell me
and some tips too. THANKS!

[S_M_A]

Try

numberSquares=areaRectangle(5,7)/areaSquare(2);

but do check your result using pen & paper. You probably would want to re-write your code after that.

[twogreenarrows]

How can i show the remainder if ever?

[S_M_A]

It depends on what you mean by the remainder but one way could be to tell if all rectangle space could be used and if not, how much space that was unusable.

[twogreenarrows]

space that is unusable

[GCDEF]

You're going about this incorrectly. Just dividing areas isn't going to give you the right result. As S_M_A said, try it with pencil and paper first, and figure out the correct algorithm before you try to code. Are you allowed to rotate rectangles?

[twogreenarrows]

help! i know that a two 2x2 square can only fit in a 4x3 rectangle. :P i need some algorithm with a remainder or excess or something

[GCDEF]

help! i know that a two 2x2 square can only fit in a 4x3 rectangle. :P i need some algorithm with a remainder or excess or something

That's kind of vague, but once you have the number of rectangles, then you can subtract the total area of the rectangles from the area of the square.

[twogreenarrows]

ohh yeah subtraction. Please help me for the algorithm,

[GCDEF]

ohh yeah subtraction. Please help me for the algorithm,

Can you rotate the rectangles?

[monarch_dodra]

Stop thinking in area and start thinking in lengths. Example:

If your rectangle is 25*35, and your squares are 3*3:
Your rectangle widths can hold 25/3 = 7 and 35/3 = 11 square widths.

This means it can hold a total of 7*11=77 squares.

Rounding down is simple, it is the default integer behavior: Nothing fancy.

I'll let you write the algorithm yourself. If I provide any more help, I'd be doing it for you.

PS. I'm assuming you can't rotate the rectangles, or place them in some crazy fonfiguration of course.

[twogreenarrows]

ok i get it now i made the algorithm but will this require me to use function?

[Lindley]

Nothing ever requires you to use functions (except main(), of course). But it's usually a good idea....

You want a function any time you have very similar code appearing multiple times in your program, or any time you can describe a task in terms of a few inputs and outputs, independent of what the rest of the logic is doing with those numbers.