Deck of card class
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  1. #1
    Join Date
    Mar 2009
    Posts
    6

    Deck of card class

    I am having trouble with a program I am trying to write and was wondering if I could get some help. I am supposed to use two arrays to store the suit and denomination of cards in a deck.

    const String suits["Clubs","Diamonds","Hearts","Spades" ]; // initialise suit array
    const String denomination["Ace","2","3","4","5","6","7","8","9","10","Jack","Queen","King"]; // initialise denom array

    Next I am supposed to have two constructors, the first takes an int between 0 and 51 inclusive as its argument, then it computes which card has that value in the deck based on the table below.

    Card number Actual Card
    ----------- -----------
    0 Ace of Clubs
    1 2 of Clubs
    2 3 of Clubs
    .
    .
    .
    9 10 of Clubs
    10 Jack of Clubs
    11 Queen of Clubs
    12 King of Clubs
    13 Ace of Diamonds
    .
    .
    .
    25 King of Diamonds
    26 Ace of hearts
    .
    .
    .
    38 King of Hearts
    39 Ace of Spades
    .
    .
    .
    51 King of Spades


    Here is how I did it

    if (number < 0 || number > 51)
    {
    printf("Invalid");
    }

    if (number >= 0 && number <= 12)
    suit = suits[0];
    else if (number >= 13 && number <= 25)
    suit = suits[1];
    else if (number >= 26 && number <= 38)
    suit = suits[2];
    else
    suit = suits[3];

    // int temp1 = number / 13;
    int temp2 = number % 13;

    value = denomination[temp2];



    The problem I am having is with the second constructor, it accepts two strings as arguments, the denomination of a card and the suit ("King","Diamonds"), I am then supposed to generate the value of this card based on the same table above. Meaning the King of Diamonds would be 25.

  2. #2
    Join Date
    May 2009
    Posts
    2,413

    Re: Deck of card class

    Use "King" and "Diamonds" to form the Actual Card entry. You get "King of Diamonds". Then scan the table from the beginning until you find this entry in the table. The corresponding Card Number entry is the number you're looking for.

    Or use the suits and denomination arrays. Find "Diamond" in suits and "King" in denomination. Then use the array positions to construct the number, like

    int number = suits_index * 13 + denomination_index;

    In the particular example it's 1*13 + 12 = 25.
    Last edited by nuzzle; August 3rd, 2010 at 10:19 PM.

  3. #3
    Join Date
    Oct 2009
    Posts
    577

    Re: Deck of card class

    To add to above comment:

    You best would add two enumerations like

    Code:
    enum { CLUB, DIAMOND, HEART, SPADE, 
                 MAX_SUIT };
    enum { ACE, ONE, TWO, THRE, FOUR, FIVE, 
                SIX, SEVEN, EIGHT, NINE, TEN, 
                JACK, QUEEN, KING,  
                MAX_RANK };
    Those enums are suitable for defining and indexing your arrays:

    Code:
    const char * suits[MAX_SUIT] = 
    {
         "Clubs","Diamonds","Hearts","Spades" 
    }; 
    
    const char * ranks[MAX_RANK] = 
    { 
         "Ace","2","3","4","5","6","7","8","9","10","Jack","Queen","King"
    };
    So for example

    cout << ranks[JACK] << " of " << suits[HEART];

    would print "Jack of Hearts";

    To compute index of 'King of Diamonds' you then would have

    index = DIAMOND * MAX_RANK + KING;

    For your constructor you would calculate

    int suit = number/MAX_RANK;
    int rank = number&#37;MAXRANK;

    and access the string arrays using those indices.

    Regards, Alex

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