Printing a String

[mmscg]

I am trying to print the contents of a buffer LPMIDIHDR lpBuffer

I am after the lpData member, and since it is declared as LPSTR

I tried doing it this way:

fprintf(fp,"lpBuffer = <%s>\n", &lpBuffer[i].lpData);

But I am only getting one character

lpBuffer = <H>

What do I have to do to print out the entire string?

This is the structure from MSDN

typedef struct midihdr_tag {
  LPSTR              lpData;
  DWORD              dwBufferLength;
  DWORD              dwBytesRecorded;
  DWORD_PTR          dwUser;
  DWORD              dwFlags;
  struct midihdr_tag *lpNext;
  DWORD_PTR          reserved;
  DWORD              dwOffset;
  DWORD_PTR          dwReserved[4];
} MIDIHDR, *LPMIDIHDR;

[cosmicvoid]

Try it without the "&" in front of lpBuffer[i].lpData, as "&lpBuffer[i].lpData" would be the address of the string pointer, not the address of the string.

[mmscg]

Thanks for offering some help.

Still not getting the results I expect.

fprintf(fp, "[%d] <%s>\n", j, lpBuffer[0].lpData);
returns
[0] <>
[1] <>
[2] <>
[3] <>
[4] <>
[5] <>
[6] <>
[7] <>
[8] <>
[9] <>
[10] <>
[11] <>
[12] <>
.
.
.

fprintf(fp, "[%d] <%s>\n", j, &lpBuffer[0].lpData[j]);
returns

[0] <>
[1] <>
[2] <>
[3] <>
[4] <>
[5] <>
[6] <>
[7] <>
[8] <ÀÔ

>
[9] <Ô

>
[10] <

>
[11] <
>
[12] <>
.
.
.

fprintf(fp, "[%d] <%s>\n", j, lpBuffer[0].lpData[j]);
returns
Unhandled exception error

[mmscg]

Changing the specifier in fprintf works with your suggestion... Thanks!

FILE *fp2;
fp2 = fopen("output2.txt", "w");
fprintf(fp2, "dwBytesRecorded = %d\n", lpBuffer[0].dwBytesRecorded);	

for (j = 0; j < (lpBuffer[0].dwBytesRecorded); j++) {
	fprintf(fp2, "[%d] <%x\n", j, lpBuffer[0].lpData[j]);
}

fclose(fp2);

returns
dwBytesRecorded = 348
[0] <0>
[1] <0>
[2] <0>
[3] <0>
[4] <0>
[5] <0>
[6] <0>
[7] <0>
[8] <ffffffc0>
[9] <ffffffd4>
[10] <1>
[11] <1>
[12] <0>
.
.
.

[MrViggy]

Changing the specifier in fprintf works with your suggestion... Thanks!

FILE *fp2;
fp2 = fopen("output2.txt", "w");
fprintf(fp2, "dwBytesRecorded = %d\n", lpBuffer[0].dwBytesRecorded);	

for (j = 0; j < (lpBuffer[0].dwBytesRecorded); j++) {
	fprintf(fp2, "[%d] <%x\n", j, lpBuffer[0].lpData[j]);
}

fclose(fp2);

returns
dwBytesRecorded = 348
[0] <0>
[1] <0>
[2] <0>
[3] <0>
[4] <0>
[5] <0>
[6] <0>
[7] <0>
[8] <ffffffc0>
[9] <ffffffd4>
[10] <1>
[11] <1>
[12] <0>
.
.
.

Yep, because lpData is not a string, it's the MIDI data:

http://msdn.microsoft.com/en-us/libr...=VS.85%29.aspx

Viggy