## To print the given graph using 3 conditions(done wid 2 stuck with 3rd)

A program has following 3 parts

1). write a program which calculates the value of Y for valid inputs of -10<= X <=10for a function Y=10*sin(X*18).

2). An extension to this program which prints a line of 21 characters with an asterix "*" at the value of Y with the 0 position shown by "|" . When Y=0 a " *" has to be printed instead of |. (Note: At one particular value of Y only one line shud be printed i.e if Y=5 then

Code:
`*    |`
shud be printed only

if Y-=5 then
Code:
`|    *`
shud be printed only.

3). An extension to this which creates a 21-element array to calculate and hold 21 values of Y for the given function. Then using these values we have to print 21 "-" lines as shown. Here use of functions which pass parameters in/out shud be demonstrated.

I have got the code for first 2 parts which is as shown: and is working properly...
Code:
```#include <hidef.h>      	  /* common defines and macros */
#include <mc9s12dp512.h>     	/* derivative information */

#include <hidef.h>      	  /* common defines and macros */
#include <mc9s12dp512.h>     	/* derivative information */

// NOTE MUST put this header file in beside main.c to use ascii/float
#include "term.h"           /* functions to support simulator terminal */
#include <math.h>

#define LINE_LENGTH 21

void main(void)
{
char rx_msg[LINE_LENGTH]="";                 //stores character array of length 21 for input
char tx_msg[LINE_LENGTH]="" ;                 // stores character array of length 21 for output

int j, spaces, temp;

PeriphInit();                               // Microcontroller initialization
EnableInterrupts;

sendmessage("\nenter value of x");
getmessage(rx_msg);                           // input the value of x
x = atoi(rx_msg);                             // convert character value of x to integer

if((x>=-10) && (x<=10))

{
y = 10 * sin(xinradians*18);                // calculating value for y
ftoa(y,tx_msg);                             // converting y from floating to character
sendmessage("The value of y is");

sendmessage(tx_msg);                        // output the value of y

}

else
{
sendmessage("Invalid Number");
}

temp=y;                                          //storing the value of y in integer variable temp

sendmessage("\n\n");
if(temp<0)                                     //condition for temp values less than 0

{                                              // calculating the desired spaces
spaces=10-(temp*(-1));                      // initialising counter variable j=0
j=0;
while(j<spaces)                            // loop for printing spaces
{
sendmessage(" ");
j++;
}

sendmessage("*");                            // printing * after the spaces
spaces= 9-spaces;                            // calculating new value for spaces after *
j=0;
while(j<spaces)                              // loop to print spaces
{
sendmessage(" ");
j++;

}

sendmessage("|");                            // printing | at 0th position
}

if(temp==0)                                  // condition for temp value equal 0

{
spaces = 9 - temp;                       // calculating desired value of spaces

j=0;
while(j<spaces)                          // loop to print spaces
{
sendmessage(" ");
j++;
}

sendmessage("*");                        // display * at temp=0

}

if(temp>0)                                   // condition for temp values greater than 0

{
j=0;
while(j<10)                                  // loop to display spaces
{
sendmessage(" ");
j++;

}
sendmessage("|");                            // printing | at 0th position
spaces= temp -1;                             // calculating spaces after |
j=0;

while(j<spaces)                              // loop to print spaces after |

{
sendmessage(" ");
j++;

}

sendmessage("*");                         // printing * after desired spaces
}

}                                                  //end main```
The desired output which i got after first 2 parts is as shown:
Code:
```*         |
*        |
*       |
*      |
*     |
*    |
*   |
*  |
* |
*|
*
|*
| *
|  *
|   *
|    *
|     *
|      *
|       *
|        *
|         *```
I am stuck with the 3rd part. Some1 plz help me out with 3rd part. The final output after all 3 sections completed is as :

Code:
```*         |
*        |
*       |
*      |
*     |
*    |
*   |
*  |
* |
*|
----------*----------
|*
| *
|  *
|   *
|    *
|     *
|      *
|       *
|        *
|         *```