Press Enter Twice

[Igor Vartanov]

You need to understand the code you write. Precisely, what count means and how it differs from pressCount.

Then you need to think about exact meaning of "press Enter twice". If you press Enter and wait 24 hours before pressing Enter second time, will it be two "single presses" or a single "press twice"? Your code tells me the second is true. Now you tell yourself whether it is.

[hypheni]

if (count != 0)

where did you defined count ?

[alone882]

Sry, but this code wont work I try

switch( Key )
  {
   case  'VK_RETURN':
   { 
      pressCount = ++pressCount % 2 }
      if (pressCount != 0)
      {
         //first time
      }
      else
      {
         //second time
         pressCount = 0;
      }

   break;

And

int pressCount = 0;
switch( Key )
  {
   case 'VK_RETURN:
   {
      if (pressCount == 0)
      {
         //first time
         ++pressCount;
      }
      else
      {
         //second time
         pressCount = 0;
      }
    }
   break;

No one will work

[alone882]

Pls somebody help :/

[Igor Vartanov]

No one will work

... until you make pressCount be static.

[alone882]

Finally I figure out how to solve this problem, thank you Igor

[Igor Vartanov]

You're welcome.

[Amleto]

count isnt defined anywhere (in scope or in class declaration)

[hypheni]

If still not solved here is code snippet.

BOOL CTESDlg::PreTranslateMessage(MSG* pMsg)
{
	static int co = 0;

	if (pMsg->message == WM_KEYDOWN && pMsg->wParam == VK_RETURN)
	{
		pMsg->wParam = NULL;
		++co;

		if (co==2)
			AfxMessageBox(L"Twice Pressed");
	}
	
	return CDialog::PreTranslateMessage(pMsg);
}