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  1. #1
    Join Date
    Feb 2011
    Location
    Iowa
    Posts
    1

    General issue - new to C++

    Question, I've had this same general compile error for everything I've tried to program in C++. I teaching myself C++ for all my classes this semester, having only studied Java so far, and I just feel like I'm missing something. Below is an example of something I'm trying to do.

    Disregard all of the #include statements as this is a test class. Basically, I want to just split a string into an array delimited by whitespace, yet I keep getting the following compilation errors:


    test.cpp: In function ‘int main()’:
    test.cpp:32: error: ‘split’ was not declared in this scope
    test.cpp: At global scope:
    test.cpp:37: error: expected unqualified-id before ‘[’ token
    test.cpp:48: error: ‘arguments’ was not declared in this scope
    test.cpp:49: error: expected unqualified-id before ‘for’
    test.cpp:49: error: expected constructor, destructor, or type conversion before ‘<=’ token
    test.cpp:49: error: expected constructor, destructor, or type conversion before ‘++’ token
    test.cpp:53: error: expected unqualified-id before ‘return’
    test.cpp:54: error: expected declaration before ‘}’ token
    jregan@ubuntu:~/Dropbox/code/OS.HW1$

    I am most confused by the one that says "‘split’ was not declared in this scope" as it keeps popping up regardless of which class/function that I attempt to compile. What am I doing wrong? (Some help clarifying the others wouldn't hurt either). Am I failing because I am too java-minded?

    Thanks in advance.


    #include <iostream>
    #include <sstream>
    #include <stdio.h>
    #include <stdlib.h>
    #include <unistd.h>
    #include <sys/types.h>
    #include <sys/stat.h>
    #include <fcntl.h>
    #include <jEshHeader.h>
    #include <string>
    #include <vector>



    using namespace std;

    int main (){


    string str("Hi my name is unaligned and who are you");
    string arguments[MAX_ARGS];
    split(arguments, str);


    }

    string[] split(string arguments[], string str){

    string buffer;
    stringstream ss(str);
    int counter = 0;

    while (ss >> buffer)
    arguments[counter] = buffer;
    counter++;
    }


    // testing whether the arguments were put into the array
    int arrSize = sizeof arguments / sizeof(int);
    for (int i = 0; i <= arrSize; i++){
    cout << arguments[i];
    cout << "\n";
    }
    return arguments;
    }

    }

  2. #2
    Join Date
    Jul 2002
    Location
    Portsmouth. United Kingdom
    Posts
    2,727

    Re: General issue - new to C++

    In C++ functions must be declared before use. Move the definition of 'split' above 'main'

    The way you are calling it, 'split' should return 'void'.
    It would be better to pass a reference to a vector of strings rather than an array.

    Code:
    void split(vector<string> &arguments, const string &str){
        
            string buffer;
            stringstream ss(str);
    
            while (ss >> buffer)
                arguments.push_back(buffer);
    }
    "It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong."
    Richard P. Feynman

  3. #3
    Join Date
    Jul 2002
    Location
    Portsmouth. United Kingdom
    Posts
    2,727

    Re: General issue - new to C++

    Better still


    Code:
    void split(vector<string> &arguments, const string &str)
    {
         istringstream iss(str);
    
         copy(istream_iterator<string>(iss), istream_iterator<string>(), back_inserter(arguments));
    }
    "It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong."
    Richard P. Feynman

  4. #4
    Join Date
    Jul 2002
    Location
    Portsmouth. United Kingdom
    Posts
    2,727

    Re: General issue - new to C++

    This may work too (untested)

    void split(vector<string> &arguments, const string &str)
    {
    istringstream iss(str);

    arguments.assign(istream_iterator<string>(iss), istream_iterator<string>());
    }
    "It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong."
    Richard P. Feynman

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