Pass arguments to typedef?

[lawl_rock]

I am typedefing a boost::multi_array as follows:

typedef boost::multi_array<int, 3> _3DArray;

If I wanted to be able to choose what type to make that _3DArray, what would I have to do? I was imagining something along the lines of:

typedef boost::multi_array<typename t, 3> _3DArray<typename t>;

where you would simply declare the _3DArray with your chosen type. Obviously, this code does not work. How would I actually do this?
Thank you in advance

[Russco]

That is a 'template typedef'. Up until C++0x they didn't exist, and I am not sure if they exist in C++0x either. They can be simulated somewhat, details here and here.

[Lindley]

It''s called a template alias in C++0x. Few compilers support it.

However, you can do this:

template <typename T>
struct MyArray3D: private boost::multi_array<T,3>
{

}

Note, you'll need to define all the constructors you want to use, and a few other operations in order for this to work as a drop-in. But it is doable.