Undefinded problem...

[aaronking]

Hello,

I have the following JavaScript:

var ev_index = "001";

if (ev_index == "001")
  {
  return "hello";
  }

if the var ev_index does not = to 001 I want it to exit and not do anything.

at the minute it returns undefinded.

Does anyone know how to just exit the if statement without returning anything.

Thanks.

[PeejAvery]

Only functions can return a value. You are looking for break.

[aaronking]

Hello,

I have now done the following:

var ev_index = "001";

if (ev_index == "001")
{
	return "hello";
}
else
{
	break;
}

If the ev_index = 001 it works fine

but, If the ev_index = any other number it comes up with a Syntax error. (invalid break statement)

Am I using the break correct ?

Aaron.

[PeejAvery]

No. It is not correct. As I said in my previous post, you cannot use return in a in if() statement. Only functions have returns. Hence why you are getting an undefined return.

But, why even bother checking the positive if you only want to check for a negative? Save yourself some code.

if (ev_index != "001") {
	// do processing here
}