Program help please.
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Thread: Program help please.

  1. #1
    Join Date
    Sep 2011

    Program help please.

    Hello guys! I am new to these forums and to programming in general. I have a program I am having some trouble with and was wondering if maybe any of you guys could help me. It runs fine until it gets to where it is suppose to use the math equation. Here is what I have so far.

    #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>

    int main()
    int choice, input;
    float temp, fahren, celsius;

    printf ("\n\t\tRelationship between Fahrenheit and Celsius");
    printf ("\n\n\t\t\t\t1) F - > C");
    printf ("\n\t\t\t\t2) C - > F");
    printf ("\n\n\t\t\tChoice (1/2) ?");
    scanf ("%i", &choice);

    if (choice == 1)
    { printf ("\n\n\t\t\tInput F:");
    scanf ("%f", &temp);
    fahren = (9.0 / 5.0) * (temp + 32.0);
    printf ("\n\n\t\t\t%.2fF = %4.2fC");

    else if (choice == 2)
    { printf ("\n\n\t\t\tInput C:");
    scanf ("%f", &temp);
    celsius = (5.0 / 9.0) * (temp - 32.0);
    printf ("\n\n\t\t\t%.2fC = %4.2fF");

    else if (choice > 2)
    { printf ("\n\n\t\t\tEnter 1 or 2 please.");


    return 0;

    This is what it is suppose to look like.

    Relationship between Fahrenheit and Celsius

    1 ) F - > C
    2 ) C - > F

    Choice (1/2)?

    Input F:100

    100.00F = 37.78C

    Do more (Y/N)?

  2. #2
    Join Date
    Aug 2009

    Re: Program help please.

    Do you have to do this with C or can you use C++?

    To address your question...

    In each case, you calculate the value, but you never actually output the calculated value (or the value given to you by the user). In addition, you will need a while loop to get the "Do More (Y/N)? behavior you are looking for. Also, it looks like you mixed up your cases. Might cause a little confusion. Lastly, your equations are off slightly.
    Last edited by Alterah; September 18th, 2011 at 12:35 AM.

  3. #3
    Join Date
    Sep 2011

    Re: Program help please.

    Ah, I figured it out. Thank you.

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